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Nezavi [6.7K]
3 years ago
15

2. What is the acceleration of an object thrown vertically down with a speed of 10 m/s?

Physics
1 answer:
Oksi-84 [34.3K]3 years ago
6 0

Answer:

Explanation:

on earth, objects in free fall accelerate downward at approximately 10 m/s²

any small initial velocity is irrelevant.

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How would you calculate power if work is not done?
Brilliant_brown [7]

Explanation:

This how you do it..

Calculate Watt-hours Per Day. Device Wattage (watts) x Hours Used Per Day = Watt-hours (Wh) per Day. ...

Convert Watt-Hours to Kilowatts. Device Usage (Wh) / 1000 (Wh/kWh) = Device Usage in kWh. ...

Find Your Usage Over a Month.

7 0
4 years ago
Basalt, formed from magma, contains iron-rich minerals. Why is this important?
Svetach [21]
Iron is a magnetic metal, and it is essential to the Earth's magnetic field!
Essentially it "records" (stores the information, maintains) the direction and orientation of the magnetic field.

Among others, the magnetic field protects the Earth from dangerous cosmic rays. 
5 0
3 years ago
How much net force is required to accelerate a 2000 kg car at 3.00 m/s^2
andrezito [222]

The net force required to accelerate a car is 6000 N.

Force is defined as the product of the mass and acceleration of the body. Force is used to changing the velocity that is to accelerate an object or a body of a particular mass. The unit of Force is Newton or kg m/s^2.

The formula used to calculate the net force is :

F = ma

where, F = Force

m = mass = 2000 kg

a = acceleration = 3.00 m/s^2

∴ F = 2000*3

F = 6000 N

Thus, to accelerate the car at 3.00 m/s^2 of mass 2000 kg net force required is 6000 N.

To learn more about force,

brainly.com/question/1046166

6 0
2 years ago
A 50-g cube of ice, initially at 0.0°C, is dropped into 200 g of water in an 80-g aluminum container, both initially at 30°C.
MakcuM [25]

Answer:

b. 9.5°C

Explanation:

m_i = Mass of ice = 50 g

T_i = Initial temperature of water and Aluminum = 30°C

L_f = Latent heat of fusion = 3.33\times 10^5\ J/kg^{\circ}C

m_w = Mass of water = 200 g

c_w = Specific heat of water = 4186 J/kg⋅°C

m_{Al} = Mass of Aluminum = 80 g

c_{Al} = Specific heat of Aluminum = 900 J/kg⋅°C

The equation of the system's heat exchange is given by

m_i(L_f+c_wT)+m_wc_w(T-T_i)+m_{Al}c_{Al}=0\\\Rightarrow 0.05\times (3.33\times 10^5+4186\times T)+0.2\times 4186(T-30)+0.08\times 900(T-30)=0\\\Rightarrow 1118.5T-10626=0\\\Rightarrow T=\dfrac{10626}{1118.5}\\\Rightarrow T=9.50022\ ^{\circ}C

The final equilibrium temperature is 9.50022°C

4 0
4 years ago
Types of mechanical waves include
USPshnik [31]
I think surface waves
4 0
4 years ago
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