The mass of nitrogen collected is mathematically given as
M-N2=0.025gram
<h3>What is the mass of nitrogen collected?</h3>
Question Parameters:
A sample weighing 2.000g
the liberated NH3 is caught in 50ml pipeful of H2SO4 (1.000ml = 0.01860g Na2O).
T=26.3c=299.3K
Pressure=745mmHg=745torr
Pressure of N2=745-25.2=719.8torr
Generally, the equation for the ideal gas is mathematically given as
PV=nRT
Therefore
719.8/760=45.6/1000=n*0.0821*299.3
n=0.00176*14
In conclusion, the Mass of N2
M-N2=0.00176*14
M-N2=0.025gram
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Answer:
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Explanation:
The curvature of the bowl would likely focus the light to a single point or area above it. This higher intensity area would be more dangerous to look at.
Answer: 1.5
Explanation:
Just took the test on E2020!
Answer:
Option B
Covalent Bonding
Explanation:
Covalent bonds in C2H5OH are formed between the carbon and hydrogen atoms, where there are shared electron pairs.
This is a weak form of attraction that holds the C2H5OH molecule together, and can easily be broken by a polar solvent such as water.
In order for water to be able to dissolve the C2H5OH molecule, it must break the covalent bonding present in the molecule
Answer:
1. final pressure = 0.259atm
2. 196.84mmHg
Explanation:
Using Boyle's law of equation
P1V1 = P2V2
Where;
P1 = initial pressure (atm)
P2 = final pressure (atm)
V1 = initial volume (mL)
V2 = final volume (mL)
According to the information given in this question:
V1 = 105mL
V2 = 352mL
P1 = 0.871atm
P2 = ?
Using P1V1 = P2V2
P2 = P1V1/V2
P2 = 0.871 × 105/352
P2 = 91.455/352
P2 = 0.2598
P2 = 0.259atm
To convert 0.259atm of the gas into mmHg, we multiply the value in atm by 760.
Hence, 0.259 × 760
= 196.84mmHg
