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jeka57 [31]
2 years ago
7

Changes in temperature, pressure, and volume affect the behavior of gases more than they affect solids and liquids. ____________

___
True false question.
True
False
Chemistry
1 answer:
Marina CMI [18]2 years ago
4 0
True. All of those things affect gases more.
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When temperatures are below freezing, the temperature at which air becomes saturated leading to the formation of frost is the
12345 [234]

Answer:

The answer is Frost Point.

Explanation:

The temperature to which the air must be cooled, with constant pressure, to reach saturation (in relation to liquid water), is called the dew point. The dew point gives a measure of the water vapor content in the air. The higher, the greater the concentration of water vapor in the air. However, when cooling produces saturation at a temperature of 0 ° C or less, the temperature is called a frost point. The water vapor is deposited as frost on a surface whose temperature is below the dew point.

4 0
3 years ago
Please help..... who is up for a zoom to help me with balancing equations ​
Alex787 [66]

Answer:

Um I can help but not on zo.om. I can help u on here just post ur question and I will answer it

8 0
3 years ago
Read 2 more answers
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evablogger [386]

Answer:

!atoms in the nitrogen family.. have 5 valence electrons. They tend to share electrons when they bond. Other elements in this family are phosphorus, arsenic, antimony, and bismuth.

5 0
3 years ago
A hiker has packed a bag of chips as a snack. At the start of the hike the pressure was 1.5 atm and the temperature was 35*C. At
Mazyrski [523]
According to <span>Gay-Lussac's Law the temperature and Pressure are directly proportional to each other if the amount and volume of given gas are kept constant.
Mathematically for initial and final states it is expressed as,

                                          P</span>₁ / T₁  =  P₂ / T₂     ----- (1)
Data Given;
                  P₁  =  1.5 atm

                  T₁  =  35 °C + 273  =  308 K

                  P₂  =  ?

                  T₂  =  0 °C + 273  =  273 K

Solving Eq. 1 for P₂,

                                   P₂  =  P₁ T₂ / T₁

Putting values,
                                   P₂  =  (1.5 atm × 273 K) ÷ 308 K

                                   P₂  =  1.32 atm
Result:
           As the temperature is decreased so the pressure also decreases from 1.5 atm to 1.32 atm. Therefore the bag will contract.
5 0
3 years ago
Which atom’s ionization energy is greater than that of phosphorus (P)? A. Ba B. K C. As D. Cl
WINSTONCH [101]

Answer is: D. Cl (chlorine).

The ionization energy (Ei) is the minimum amount of energy required to remove the valence electron, when element lose electrons, oxidation number of element grows (oxidation process).

Barium, potassium and arsenic are metals (easily lost valence electrons), chlorine is nonmetal (easily gain electrons).

Alkaline metals (in this example, potassium) have lowest ionizations energy and easy remove valence electrons (one electron), earth alkaline metals (in this example, barium) have higher ionization energy than alkaline metals, because they have two valence electrons.

Nonmetals (in this example chlorine) are far right in the main group and they have highest ionization energy, because they have many valence electrons.

5 0
3 years ago
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