Answer:
-35 degrees F
When mixed in equal parts with water (50/50), antifreeze lowers the freezing point to -35 degrees F and raises the boiling temperature to 223 degrees F. Antifreeze also includes corrosion inhibitors to protect the engine and cooling system against rust and corrosion.
Answer:
The maximum length of a surface flaw is 8.24 μm
8.24 μm
Explanation:
Given that:
The modulus of elasticity E = 69 GPa
The specific surface energy 
= 0.3 J/m²
The length of the surface flaw "a" = ??
From the theory of the brittle fracture;
Making a the subject of the formula; we have:
a = 8.24 × 10⁻⁶ m
a = 8.24 μm
Thus; the maximum length of a surface flaw is 8.24 μm
Answer:
Area under the strain-stress curve up to fracture gives the toughness of the material.
Explanation:
When a material is loaded by external forces stresses are developed in the material which produce strains in the material.
The amount of strain that a given stress produces depends upon the Modulus of Elasticity of the material.
Toughness of a material is defined as the energy absorbed by the material when it is loaded until fracture. Hence a more tough material absorbs more energy until fracture and thus is excellent choice in machine parts that are loaded by large loads such as springs of trains, suspension of cars.
The toughness of a material is quantitatively obtained by finding the area under it's stress-strain curve until fracture.
Answer:
4.536hp
Explanation:
The decrease in the heat gain of the room is determined from difference in electrical inputs:
Answer:
Percent Elongation = 52.72%
Percent Reduction in Area = 64%
Explanation:
First we find percent elongation:
Percent Elongation = {Final Gage Length - Initial Gauge Length/Initial Guage Length} x 100%
Percent Elongation = {(4.20 in - 2.75 in)/2.75 in} x 100%
<u>Percent Elongation = 52.72%</u>
Now, for the percent reduction in area:
Percent Reduction in Area = {Final Cross Sectional Area - Initial Cross Sectional Area|/Initial Cross Sectional Area Length} x 100%
Percent Reduction in Area = {π(0.3 in)² - π(0.5 in)²/π(0.5 in)²} x 100%
<u>Percent Reduction in Area = - 64%</u>
here, negative sign shows a decrease in area.
