2 years ago

Cu(OH)₂ +H₃PO₄ = Cu₃(PO₄)₂+H₂O how do i balance this equation

1 answer:

swat322 years ago

3 0

balanced equation =

3Cu(OH)2 + 2H3PO4 → Cu3(PO4)2 + 6H2O

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sesenic [268]

Answer: The concentration of $Cl^-$ ions in the resulting solution is 1.16 M.

Explanation:

To calculate the molarity of the solution after mixing 2 solutions, we use the equation:

$M=\frac{n_1M_1V_1+n_2M_2V_2}{V_1+V_2}$

where,

$n_1,M_1\text{ and }V_1$ are the n-factor, molarity and volume of the $CaCl_2$

$n_2,M_2\text{ and }V_2$ are the n-factor, molarity and volume of the $AlCl_3$

We are given:

$n_1=2\\M_1=0.276M\\V_1=155mL\\n_2=3\\M_2=0.471M\\V_2=384mL$

Putting all the values in above equation, we get

$M=\frac{(2\times 0.276\times 155)+(3\times 0.471\times 384)}{155+384}\\\\M=1.16M$

The concentration of $Cl^-$ ions in the resulting solution will be same as the molarity of solution which is 1.16 M.

Hence, the concentration of $Cl^-$ ions in the resulting solution is 1.16 M.

6 0

3 years ago

Mariulka [41]

I think the answer is 2Mg + H2O4 = Cu12O4 + 2H

I’m really not sure though so it might be wrong… I’m not the best at balancing equations lol

6 0

1 year ago

Varvara68 [4.7K]

the SI unit of mass is kilogram

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2 years ago

mihalych1998 [28]

Answer:

Here is your answer mate :D

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2 years ago

fiasKO [112]

Answer:

Explanation:

5 0

2 years ago