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Andreas93 [3]
2 years ago
14

Tec A says that high octane fuel is harder to ignite than lower octane. Tec B says that using high octane fuel in an engine desi

gned for lower octane will produce better fuel economy and power. Who is correct?
Engineering
2 answers:
vlada-n [284]2 years ago
7 0

Answer:

To my understanding higher octane fuel has a higher detonation point, so you compress it more, which will result in more power. Also yes higher octane fuel in a car expecting lower should get better gas mileage and efficiency.

Explanation:

Kryger [21]2 years ago
3 0

Answer:

Tec A says that high octane fuel is harder to ignite than lower octane. Tec B says that using high octane fuel in an engine designed for lower octane will produce better fuel economy and power. Who is correct?

Explanation:

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Consider a CMOS inverter which has ideal transistors with the following characteristics: PMOS transistor: W/L = 2; Mobility (up)
yaroslaw [1]

Answer:

The transistor will be in amplifier mode and we will expect current will be higher than expected.

6 0
3 years ago
g The parameters of a certain transmission line operating at 휔휔=6 ×108 [rad/s] are 퐿퐿=0.35 [휇휇H/m], 퐶퐶=75 [pF/m], 퐺퐺=75 [휇휇S/m],
yKpoI14uk [10]

Explanation:

\begin{aligned}\gamma &=\sqrt{Z Y}=\sqrt{(R+j \omega L)(G+j \omega C)} \\&-\sqrt{|17|} j\left(6 \times 10^{8}\right)\left(0.35 \times 10^{-6}\right)|| 75 \times 10^{-6}\left|j\left(6 \times 10^{8}\right)\left(40 \times 10^{-12}\right)\right| \\&=0.094+j 2.25 \mathrm{m}^{-1}-\alpha+j \beta\end{aligned}

Therefore,

-\alpha-0.094 \mathrm{Np} / \mathrm{m} . \quad 3-2.25 \mathrm{rad} / \mathrm{m}, \text { and } \lambda-2 \pi / \beta-\underline{2.79} \mathrm{m}

Z_{0}-\sqrt{\frac{Z}{Y}}-\sqrt{\frac{R+j \omega L}{G+j \omega C}}-\sqrt{\frac{17+j 2.1 \times 10^{2}}{75 \times 10^{-6}+j 2.4 \times 10^{-2}}}-\frac{93.6-j 3.64 \Omega}{4}

5 0
3 years ago
Determine (with justification) whether the following systems are (i) memoryless, (ii) causal, (iii) invertible, (iv) stable, and
lina2011 [118]

Answer:

a.

y[n] = x[n] x[n-1]  x[n+1]

(i) Memory-less - It is not memory-less because the given system is depend on past or future values.

(ii) Causal - It is non-casual because the present value of output depend on the future value of input.

(iii) Invertible - It is invertible and the inverse of the given system is \frac{1}{x[n] . x[n-1] x[n+1]}

(iv) Stable - It is stable because for all the bounded input, output is bounded.

(v) Time invariant - It is not time invariant because the system is multiplying with a time varying function.

b.

y[n] = cos(x[n])

(i) Memory-less - It is memory-less because the given system is not depend on past or future values.

(ii) Causal - It is casual because the present value of output does not depend on the future value of input.

(iii) Invertible - It is not invertible because two or more than two input values can generate same output values .

For example - for x[n] = 0 , y[n] = cos(0) = 1

                       for x[n] = 2\pi , y[n] = cos(2\pi) = 1

(iv) Stable - It is stable because for all the bounded input, output is bounded.

(v) Time invariant - It is time invariant because the system is not multiplying with a time varying function.

3 0
3 years ago
How wold you classify the earliest examples of S.T.E.M discoveries provided in this lesson?
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Answer:

the answer is C

Explanation:

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3 years ago
A device that transforms electrical energy to mechanical:
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Answer:

electric motor

*** brainly if possible

Explanation:

3 0
3 years ago
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