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yanalaym [24]
3 years ago
10

A duck with a mass of 0.90 kilograms flies at a rate of 12.0 m/s. What is the kinetic energy of the duck?

Physics
2 answers:
Pepsi [2]3 years ago
7 0

Answer:

Duck's kinetic energy is 64.8 Joules

Explanation:

It is given that,

Mass of the duck, m = 0.9 kg

Velocity of the duck is, v = 12 m/s

We have to find the velocity of the duck. It is given due to the motion of an object. Mathematically, it is written as :

KE=\dfrac{1}{2}mv^2

KE=\dfrac{1}{2}\times 0.9\ kg\times (12\ m/s)^2

KE = 64.8 Joules

Hence, the kinetic energy of the duck is 64.8 Joules              

bija089 [108]3 years ago
6 0
It should be at about 65J. Not sure, hope I helped.
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Two electrons are separated by a distance of 3.00 x 10^-6 meter. What are the magnitude and direction of the electrostatic force
Brilliant_brown [7]
The electrostatic force between two charges q1 and q2 is given by
F=k_e  \frac{q_1 q_2}{r^2}
where 
k_e = 8.99 \cdot 10^9 N m^2 C^{-2} is the Coulomb's constant
r=3.00 \cdot 10^{-6} m is the distance between the two charges.

In our problem, the two charges are two electrons, so their charges are equal and equal to 
q_1=q_2=q=-1.6 \cdot 10^{-19}C

By substituting these values, we find the intensity of the force between the two electrons:
F=(8.99 \cdot 10^9 N m^2 C^{-2})  \frac{(-1.6 \cdot 10^{-19}C)(-1.6 \cdot 10^{-19}C)}{(3.00 \cdot 10^{-6} m)^2}=2.6 \cdot 10^{-17}N

This is the magnitude of the force each electron exerts to the other one. The direction is given by the sign of the charges: since the two electrons have same charge, they repel each other, so the force exerted by electron 1 is toward electron 2 and viceversa.
5 0
3 years ago
Which are parts of the middle ear? Check all that apply.
stellarik [79]

Answer:

middle ear has three bones! the hammer, anvil, stirrup, and ear drum

Explanation:

5 0
3 years ago
An exoplanet has three times the mass and one-fourth the radius of the Earth. Find the acceleration due to gravity on its surfac
Harlamova29_29 [7]

Answer:

b. 48.0 g.

Explanation:

Given;

mass of the exoplanet, M_p = 3M_e

radius of the exoplanet, r_p = \frac{1}{4} r_e

The acceleration due to gravity of the planet is calculated as;

g_p = \frac{GM_p}{r_p^2} \\\\for \ Earth's \ surface\\\\g = \frac{GM_e}{r_e^2} \\\\G = \frac{gr_e^2}{M_e} = \frac{g_pr_p^2}{M_p} \\\\\frac{gr_e^2}{M_e} = \frac{g_p(\frac{r_e}{4}) ^2}{3M_e} \\\\\frac{gr_e^2}{M_e} = \frac{g_pr_e ^2}{16\times 3M_e} \\\\g = \frac{g_p}{48} \\\\g_p = 48  \ g

Therefore, the correct option is b. 48.0 g

5 0
2 years ago
How long does it take light to reach us from the Sun, 1.53x108 km away? Give your answer in minutes.
muminat

Answer:

Sun light takes 8.5 minutes to reach Earth.

Explanation:

Light travels in vacuum at constant speed c= 3 \times 10 ^8 \cfrac ms, so we can find the time it takes to travel the given distance from Earth to Sun using a kinematic equation.

Finding the time it takes for Sun light to reach us.

Using the kinematic equation d = vt, we can solve for time t, which will give us

t = \cfrac dv

We can replace the equation with the given values, but before doing that, we need the values to be on SI units, thus the distance becomes

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Replacing the values on the time equation give us

t = \cfrac{1.53 \times 10^{11} m}{3 \times 10^{8} \cfrac ms}\\t = 510 s

We get as result 510 seconds, then we must convert them in minutes.

t = 510 s \times \cfrac{1 min}{60s}\\\boxed{t = 8.5 min }

So we can conclude that Sun light takes 8.5 minutes to reach Earth.

7 0
3 years ago
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