Two cranes each lift containers with the same mass to the same height. The first crane takes 47 seconds, while the second crane

A 1500-kg car accelerates from rest to 25 m/s in 7.0 s. what is the average power delivered by the engine? (1 hp = 746 w)

AVprozaik [17]

The solution for this is:
Work done = force * distance = m*a*d and power = energy/time
The vo=0 and vf = 25 m/s and t=7 sec. This gives...
3.6 m/s^2 as acceleration and d=87.5 meters and thus F=ma= 5400 N.
Energy = 5400*87.5 = 4.7E5 Joules (2 sig. figs) and Power = 67,500 Watts or 90 HP (2 sig. figs again).

5 0

3 years ago

Read 2 more answers

Plz help me im really confused. The questions are in the second pic and the vehicles are in the first the fetures are in the las

kirill115 [55]

Answer:

1.ima say car 2 is safer than car 1.

2.airbags: airbags make it safer because if you get in a reck they will protect you againsed more harm then if you didnt have airbags.

breaking distance: it takes less distance to stop so if there was a reck up the streat you could stop and turn around so you wouldnt get into that wreck.

accrleration: it can make you go faster so incase someoe behind you is speading you could speadup and turn into a parking lot and you wouldent get hurt.

3. car 2 is safer because it has breaking distance and it can stop you way before you get into a wreck than car 1 that doesnt have that ability

Explanation: ima award myself brainliest. Dont ask why i just answerd my own question on here. Yay

5 0

3 years ago

Find the acceleration produced.

krok68 [10]

Answer:

0.67m/s²

Explanation:

Given parameters:

Mass of toy = 1.2kg

Force applied = 0.8N

Unknown:

Acceleration = ?

Solution:

According to newton's second law of motion;

Force = mass x acceleration

Now,

Acceleration = $\frac{Force}{mass}$

Acceleration = $\frac{0.8}{1.2}$ = 0.67m/s²

4 0

3 years ago

Read 2 more answers

A 100-kg spacecraft is in a circular orbit about Earth at a height h = 2RE .

maria [59]

To solve this problem it is necessary to apply the concepts related to the conservation of the Gravitational Force and the centripetal force by equilibrium,

$F_g = F_c$

$\frac{GmM}{r^2} = \frac{mv^2}{r}$

Where,

m = Mass of spacecraft

M = Mass of Earth

r = Radius (Orbit)

G = Gravitational Universal Music

v = Velocity

Re-arrange to find the velocity

$\frac{GM}{r^2} = \frac{v^2}{r}$

$\frac{GM}{r} = v^2$

$v = \sqrt{\frac{GM}{r}}$

PART A ) The radius of the spacecraft's orbit is 2 times the radius of the earth, that is, considering the center of the earth, the spacecraft is 3 times at that distance. Replacing then,

$v = \sqrt{\frac{(6.67*10^{-11})(5.97*10^{24})}{3*(6.371*10^6)}}$