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3 years ago

In a 200.0-m relay race (each leg of the race is 50.0 m long), one swimmer has a 0.450 second lead

1 answer:

5 0

The minimum speed that the second swimmer must have in order to catch up with the first swimmer by the end of the pool is; 4.04 m/s

We are given the following facts;

Both swimmers swim the same distance of 50 m for a leg of the relay race.

Swimmer 1 swims at constant speed of 3.9 m/s.

Swimmer 1 has a 0.450 second head start.

Formula for time taken is;

time = distance/speed

Time taken by swimmer 1 for one leg;

t₁ = 50/3.9

t₁ = 12.82 s

Since swimmer 1 has a head start of 0.45 s, then time that swimmer 2 must use in order to catch up is;

t₂ = 12.82 -0.45

t₂ = 12.37 s

Thus, speed of swimmer 2;

v = 50/12.37

v = 4.04 m/s

Read more about distance, speed and time at; brainly.com/question/24571540

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Molecules rearrange and form new molecules reversible

STALIN [3.7K]

1. Molecules rearrange and form new molecules - exchange (they exchange some material in order to produce new things)
2. simultaneous decomposition and synthesis - reversible (it can go back)
3. bonds broken and elements released - decomposition
4. molecules formed from components - synthesis (these components merge and create molecules)

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3 years ago

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Ten identical steel wires have equal lengths L and equal "spring constants" k. The Young's modulus of each wire is Y. The wires

svlad2 [7]

Answer:

option (B)

Explanation:

Young's modulus is defined as the ratio of longitudinal stress to the longitudinal strain.

Its unit is N/m².

The formula for the Young's modulus is given by

$Y=\frac{F \times L}{A\times \delta L}$

where, F is the force applied on a rod, L is the initial length of the rod, ΔL is the change in length of the rod as the force is applied, A is the area of crossection of the rod.

It is the property of material of solid. So, when the 10 wires are co joined together to form a new wire of length 10 L, the material remains same so the young' modulus remains same.

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3 years ago

In which direction does a bag at rest move when a force of 20 newtons is applied from the right? A. in the direction of the appl

-Dominant- [34]

The correct answer is A. In the direction of applied force. This is because acceleration occurs n the direction of applied force according to Newtons second law of motion which states that the acceleration of a body is directly proportional to the applied force and takes place in the direction of force.

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3 years ago

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An object is dropped from a bridge. A second object is thrown downward 1.48 s later. They both reach the water 48.1 m below at t

pashok25 [27]

To solve this problem we will apply the linear motion kinematic equations. With the data provided we will calculate the time of the first object to fall. Later we will get the time difference between the two. This difference will allow us to find the free fall distance. Through the distance we will find the initial velocity, that is,

$x = v_0 t +\frac{1}{2}at^2$

$48.1 = 0*t + \frac{1}{2} (9.8)t^2$

$t = 3.13s$

The second object is thrown downward at one second later and it meets the first object at the water is

$t' = 3.13 -1.48$

$t' = 1.65s$

The distance of the object will travel due to free fall acceleration is

$x = v_0 t+\frac{1}{2} at^2$

$x = 0*(1.65) +\frac{1}{2}(9.8)(1.65)^2$

$x = 13.34m$

The distance of the object will travel due to its initial velocity is

$v_0 = \frac{d_0}{t}$

$d_0 = v_0 t$

$48.1-13.34 = v_0 (1.65)$

$v_0 = 21.06m/s$

Therefore the initial speed of the second object is 21.06m/s

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4 years ago

A gamma ray photon has an energy of 0.91 GeV. (1 GeV = 109 eV.) What is the wavelength of the gamma ray in fm? (1 fm = 10-15 m)?

anastassius [24]

Answer:

$\lambda=1.37 fm$

Explanation:

The Planck Eistein relation, states that the energy of a photon is proportional to its frequency:

$E=h\nu(1)$

h is the Plank constant.The frequency of a photon is defined as the speed of light over its wavelength:

$\nu=\frac{c}{\lambda}(2)$

Replacing (2) in (1):

$E=\frac{hc}{\lambda}\\\lambda=\frac{hc}{E}\\\lambda=\frac{(4.14*10^{-15}eV\cdot s)(3*10^8\frac{m}{s})}{0.91*10^{9}eV}\\\\\lambda=(1.37*10^{-15}m)*\frac{1fm}{10^{-15}m}\\\\\lambda=1.37 fm$

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3 years ago