Answer:
A few of the positive particles aimed at a gold foil seemed to bounce back.
Explanation:
By V=IR
A: 24=I*20
I = 1.2A
B: 220 = I*250
I = 0.88A
C: 6= I*3
I = 2 A
C,A,B
Answer:
Explanation:
Given:
Specific heat of gold = 0.031cal/°C
Specific heat of silver = 0.057cal/°C
To know the metals that will heat up faster, we must understand the meaning of specific heat capacity.
It is the amount of heat required to raise the temperature of 1g of a substance by 1°C.
Now,
The higher the specific heat capacity the more energy it is required to heat up the substance.
So, Gold with a specific heat capacity of 0.031cal/°C will heat up faster.
The specific heat of the substance will be 0.129 J/g°C.
<h3>What is specific heat capacity?</h3>
The amount of heat required to increase a substance's temperature by one degree Celsius is known as specific heat capacity.
Similarly, heat capacity is the relationship between the amount of energy delivered to a substance and the increase in temperature that results.
The given data in the problem is;
Q is the amount of energy necessary to raise the temperature = 3,000.0 j
M is the mass= 0.465 kg.
Δt is the time it takes to raise the temperature.=50°c
s stands for specific heat capacity=?
Mathematically specific heat capacity is given by;

Hence the specific heat of the substance will be 0.129 J/g°C.
To learn more about the specific heat capacity refer to the link brainly.com/question/2530523
Answer:
The final acceleration of the car, v = 70 m/s
Explanation:
Given,
The initial velocity of the car, u = 20 m/s
The acceleration of the car, a = 10 m/s²
The time period of travel, t = 5 s
Using the I equations of motion
v = u + at
= 20 + 10(5)
= 20 + 50
= 70 m/s
Hence, the final acceleration of the car, v = 70 m/s