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s344n2d4d5 [400]
3 years ago
6

If a neutral material like fur is rubbed on another neutral object like a rubber ball what is the resulting charges of the objec

ts?
A) The balloon becomes negatively charged and the fur becomes positively charged.

B) They both remain neutral.

C) They both become negatively charged.

D) The balloon becomes negatively charged and the fur stays neutral.

E) They both become positively charged.​​
Physics
1 answer:
mrs_skeptik [129]3 years ago
7 0
B is the right answer I hope I helped
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Two point charges, a +45nC charge X and a +12nC charge Y are separated by a distance of 0.5m.
Gnoma [55]

A) Calculate the resultant electric field strength at the midpoint between the charges.

Qx is the charge at X and Qy is the charge at Y.

E at midpoint = k×Qx/0.25² - k×Qy/0.25²

k = 9×10⁹Nm²C⁻², Qx = 45nC, Qy = 12nC

E = 4752N/C

Well done.

B) Calculate the distance from X at which the electric field strength is zero.

Let D be some point between X and Y for which the net E field is 0.

Let d be the distance from X to D.

Set up the following equation:

E at D = k×Qx/d² - k×Qy/(0.5-d)² = 0

Do some algebra to solve for d:

k×Qx/d² = k×Qy/(0.5-d)²

Qx/d² = Qy/(0.5-d)²

Qx(0.5-d)² = Qyd²

(0.5-d)√Qx = d√Qy

0.5√Qx-d√Qx = d√Qy

d(√Qx+√Qy) = 0.5√Qx

d = (0.5√Qx)/(√Qx+√Qy)

Plug in Qx = 45nC, Qy = 12nC

d ≈ 330mm

C) Calculate the magnitude of the electric field strength at the point P on the diagram below.

First determine the angles of the triangle. The sides of the triangle are 0.3m, 0.4m, and 0.5m, so this is a right triangle where the angle between the 0.3m and 0.4m sides is 90°

∠Y = tan⁻¹(0.4/0.3) = 53.13°

∠X = 90-∠Y = 36.87°

Determine the horizontal component of E at P:

Ex = E from Qx × cos(∠X) - E from Qy × cos(∠Y)

Ex = k×Qx/0.4²×cos(36.87°) - k×Qy/0.3²×cos(53.13°)

Ex = 1305N/C

Determine the vertical component of E at P:

Ey = E from Qx × sin(∠X) - E from Qy × sin(∠Y)

Ey = k×Qx/0.4²×sin(36.87°) - k×Qy/0.3²×sin(53.13°)

Ey = 2479N/C

Use the Pythagorean theorem to determine the magnitude of E at P:

E = √(Ex²+Ey²)

E ≈ 2802N/C

4 0
3 years ago
Describe how the smoke particles move when a candle was blown out?​
lukranit [14]

Answer:

When a candle was blown out, the flame stops immediately but the wick and the wax are both still hot, so pyrolysis continues for a few seconds. Explanation:

4 0
3 years ago
This diagram represents the synthesis of nitrogen monoxide. Write a balanced equation of this chemical reaction. A) N2(g) + O2(g
ruslelena [56]
The only balanced equation is B. 

If you look at the equation and break it down you can see that in:

N_{2} + O_{2}→ 2NO

Starting from the left side of the equation there are 2 Nitrogen atoms, and 2 oxygen atoms as indicated by the subscript. 

To balance the equation, the number of atoms of each element in the right side equation should be equal to left. By putting the numerical coefficient of 2, you will distribute that to each element. So you will end up with 2 nitrogen atoms and 2 oxygen atoms on the left side of the equation. Thus, the equation is balanced. 

The answer again, is B. 
4 0
3 years ago
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Which of the following will cause an increase in gas pressure in a closed container?
Volgvan
D. both b. and c. Obviously adding more gas but reducing the volume because of the limited space in the container.
5 0
4 years ago
A change to an objects motion is caused by...
andrezito [222]

Answer:

b-unbalanced forces

Explanation:

because the net force then is not a zero

4 0
3 years ago
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