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3 years ago

What is the relationship between layering of fluids and density?

1 answer:

7 0

Density of a liquid determines how it will layer (heaviest to lightest). If the liquid is least dense it will float to the bottom. Layers will remain separated because each liquid is actually floating on top of the more dense liquid beneath it.

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Which of the following is the smallest volume? (2 points) 30 cm3 2,500 mL 25 m3 2.0 x 10-1 L

aliya0001 [1]

2500mL is the answer

6 0

4 years ago

Which of the following describes when he is transferred as a form of light

pantera1 [17]

Answer:

HVL is that amount of material that will reduce the original intensity to half of its value. One HVL will reduce the 100 R/minute to 50 R/minute, a second HVL will reduce the 50 R/minute to 25 R/minute

Explanation:

5 0

3 years ago

What is Δn for the following equation in relating Kc to Kp?CH4(g) + H2O(g) ↔ CO(g) + 3 H2(g)-120-3-2

Sindrei [870]

Answer: Δn for the following equation in relating Kc to Kp is 2.

Explanation:

The balanced chemical equation is:

$CH_4(g)+H_2O(g)\rightleftharpoons CO(g)+3H_2(g)$

Relation of $K_p$ with $K_c$ is given by the formula:

$K_p=K_c(RT)^{\Delta n_g}$

Where,

$K_p$ = equilibrium constant in terms of partial pressure

$K_c$ = equilibrium constant in terms of concentration

R = Gas constant

T = temperature

$\Delta n_g$ = change in number of moles of gas particles = $n_{products}-n_{reactants}=4-2=2$

Putting values in above equation, we get:

$K_p=K_c\times (RT)^{2}$

Thus the value of Δn for the following equation in relating Kc to Kp is 2.

5 0

3 years ago

The equation for photon energy, E, is E=hc/λ

Leni [432]

Answer:

The wavelength, λ, of a photon that has an energy of E = 3.92×10⁻¹⁹ J is 5.054*10⁻⁷ m

Explanation:

The wavelength is defined for every periodic wave, that is, for the type of wave that repeats itself with exactly the same shape every given interval of time. It is the distance between two points from which the wave repeats.

Radiation is the emission, propagation and transfer of energy in any medium in the form of electromagnetic waves or particles.

The energy carried by electromagnetic radiation travels by waves. This energy is transmitted grouped in small "quanta" of energy called photons. The energy of a photon is measured in Joules (J) and is

$E=\frac{h*c}{wavelength}$

Being:

E=3.92×10⁻¹⁹ J
h= 6.626×10⁻³⁴ J⋅s (Planck's constant)
c = 2.99×10⁸ m/s (the speed of light)
wavelength=?

and replacing:

$3.92*10^{-19}J =\frac{6.626*10^{-34}J.s*2.99*10^{8}\frac{m}{s} }{wavelength}$

you get:

$wavelength =\frac{6.626*10^{-34}J.s*2.99*10^{8}\frac{m}{s} }{3.92*10^{-19}J}$

wavelength= 5.054*10⁻⁷ m

<u><em>The wavelength, λ, of a photon that has an energy of E = 3.92×10⁻¹⁹ J is 5.054*10⁻⁷ m</em></u>

6 0

3 years ago

In the following reaction, identify the oxidized species, reduced species, oxidizing agent, and reducing agent. Be sure to answe

gtnhenbr [62]

Answer :

$Cl_2$ is reduced species.

$KI$ is oxidized species.

$Cl_2$ is oxidizing agent.

$KI$ is reducing agent.

Explanation :

Redox reaction or Oxidation-reduction reaction : It is defined as the reaction in which the oxidation and reduction reaction takes place simultaneously.

Oxidation reaction : It is defined as the reaction in which a substance looses its electrons. In this, oxidation state of an element increases. Or we can say that in oxidation, the loss of electrons takes place.

Reduction reaction : It is defined as the reaction in which a substance gains electrons. In this, oxidation state of an element decreases. Or we can say that in reduction, the gain of electrons takes place.

Reducing agent : It is defined as the agent which helps the other substance to reduce and itself gets oxidized. Thus, it will undergo oxidation reaction.

Oxidizing agent : It is defined as the agent which helps the other substance to oxidize and itself gets reduced. Thus, it will undergo reduction reaction.

The balanced redox reaction is :

$Cl_2(aq)+2KI(aq)\rightarrow 2KCl(aq)+I_2(aq)$

The half oxidation-reduction reactions are:

Oxidation reaction : $2I^-\rightarrow I_2+2e^-$

Reduction reaction : $Cl_2^++2e^-\rightarrow 2Cl^-$

From this we conclude that the $'KI'$ is the reducing agent that loses an electron to another chemical species in a redox chemical reaction and itself gets oxidized and $'Cl_2'$ is the oxidizing agent that gain an electron to another chemical species in a redox chemical reaction and itself gets reduced.

Thus, $Cl_2$ is reduced species.

$KI$ is oxidized species.

$Cl_2$ is oxidizing agent.

$KI$ is reducing agent.

7 0

4 years ago