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mylen [45]
3 years ago
6

The Tampa Times polled 1,457 adults in the city to determine whether they put on their shirt before they put on their pants. Of

the respondents, 48% said they put their shirt on first. Suppose 32% of all adults actually put their shirt on first. What are the mean and standard deviation of the sampling distribution
Mathematics
1 answer:
mr Goodwill [35]3 years ago
5 0

Answer:

The mean is 0.32 and the standard deviation is 0.0122.

Step-by-step explanation:

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Help please !!:) For y =3x -2x^2 +5x^3 show how to find the value for y when x = 3
victus00 [196]

y = 3x-2x∧2+5x∧3

When we replace x with value 3 we get

y = 3 * 3 - 2 * 3∧2 + 5 * 3∧3 => y = 9-2*9+5*27 => y = 9-18+135 => y = 126

good luck!!!

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The following graphs show the performance of two stocks over the first five months of the year. A graph titled Stock A B C has m
hichkok12 [17]

Answer:

C) Stock XYZ shows the best performance. The scale of Stock XYZ makes the graph appear to be rising more slowly.

Step-by-step explanation:

i did this question on my test, from reading the graph, i am almost certain this is the answer. correct me if i am wrong!

8 0
3 years ago
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sohail earn Rs 1500000 in a year if all of this income is taxable how much income tax does he pay ? assume the income tax rate i
skelet666 [1.2K]

Answer:

Rs 105 000

Step-by-step explanation:

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Please guys help me out with this
Kisachek [45]

When you have a negative exponent, you move the variable with the negative exponent to the other side of the fraction to make the exponent positive.

For example:

x^{-2} or \frac{x^{-2}}{1} =\frac{1}{x^2}

\frac{1}{2y^{-3}} =\frac{y^3}{2}  (you don't move the "2" because "2" has an exponent of 1, only "y" has the negative exponent)

\frac{5^{-2}}{y}=\frac{1}{(5^2)y} =\frac{1}{25y}

When you multiply a variable with an exponent by a variable with an exponent, you add the exponents together. (But you can only combine the exponents when the variables are the same)

x^2(y^3)=x^2y^3     (You can't combine them because they have different variables of x and y)

x^3(x^5)=x^{(3+5)}=x^8

y^3(y^2)=y^{(3+2)}=y^5

There's two ways you can do this. Either by first making all the exponents positive then do subtraction, or multiply them then make all the exponents positive. I'm doing the 2nd way.

2w^7u^{-2}w^{-6}*9y^{-6}*2y^9u  You can combine the numbers 2 x 9 x 2 = 36

36w^7u^{-2}w^{-6}y^{-6}y^9u    Now multiply the terms with the same variables

36(w^{7+(-6)})(u^{(-2+1)})(y^{(-6+9)})    

36(w^1)(u^{-1})(y^3)     Now make all the exponents positive

\frac{36wy^3}{u}

If you were to do subtraction, here is what you need to know:

When you divide a variable with an exponent by a variable with an exponent, you subtract the exponents together. (Reminder: they have to be the same variable in order to combine the exponents)

For example:

\frac{x^3}{x^2} =x^{(3-2)}=x^1   or  x

\frac{y^2}{y^4} =y^{(2-4)}=y^{-2}=\frac{1}{y^2}

7 0
3 years ago
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