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4vir4ik [10]
2 years ago
5

Five gases combined in a gas cylinder have the following partial pressures: 3. 00 atm (N2), 1. 80 atm (O2), 0. 29 atm (Ar), 0. 1

8 atm (He), and 0. 10 atm (H). What is the total pressure that is exerted by the gases? Use mc020-1. Jpg. 5. 08 atm 5. 19 atm 5. 27 atm 5. 37 atm.
Chemistry
1 answer:
Helen [10]2 years ago
7 0

The total pressure of the gaseous mixture has been 5.37 atm. Thus, option D is correct.

The partial pressure has been defined as the pressure exerted by each gas in the mixture.

According to the Dalton's law of partial pressure, the total pressure of gas has been the sum of the partial pressure of the gases in the mixture.

The given partial pressure of gases in the mixture has been:

  • Partial pressure of Nitrogen, P_N_2=3\;\rm atm
  • Partial pressure of Oxygen, P_O_2=1.80\;\rm atm
  • Partial pressure of Argon, P_A_r=0.29\;\rm atm
  • Partial pressure of Helium, P_H_e=0.18\;\rm atm
  • Partial pressure of Hydrogen, P_H=0.10\;\rm atm

The total pressure of the gaseous mixture has been:

P=P_N_2\;+\;P_O_2\;+\;P_A_R\;+\;P_H_e\;+\;P_H\\P=3\;+\;1.80\;+\;0.29\;+\;0.18\;+\;0.10\;\text {atm}\\P=5.37\;\rm atm

The total pressure of the gaseous mixture has been 5.37 atm. Thus, option D is correct.

For more information about partial pressure, refer to the link:

brainly.com/question/14623719

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Part 1. A chemist reacted 12.0 liters of F2 gas with NaCl in the laboratory to form Cl2 gas and NaF. Use the ideal gas law equat
galben [10]

The mass of NaCl needed for the reaction is 91.61 g

We'll begin by calculating the number of mole of F₂ that reacted.

  • Volume (V) = 12 L
  • Temperature (T) = 280 K
  • Pressure (P) = 1.5 atm
  • Gas constant (R) = 0.0821 atm.L/Kmol
  • Number of mole (n) =?

PV = nRT

1.5 × 12 = n × 0.0821 × 280

18 = n × 22.988

Divide both side by 22.988

n = 18 / 22.988

n = 0.783 mole

Next, we shall determine the mole of NaCl needed for the reaction.

F₂ + 2NaCl —> Cl₂ + 2NaF

From the balanced equation above,

1 mole of F₂ reacted with 2 moles of NaCl.

Therefore,

0.783 mole F₂ will react with = 0.783 × 2 = 1.566 moles of NaCl.

Finally, we shall determine the mass of 1.566 moles of NaCl.

  • Mole = 1.566 moles
  • Molar mass of NaCl = 23 + 35.5 = 58.5 g/mol
  • Mass of NaCl =?

Mass = mole × molar mass

Mass of NaCl = 1.566 × 58.5

Mass of NaCl = 91.61 g

Therefore, the mass of NaCl needed for the reaction is 91.61 g

Learn more about stiochoimetry: brainly.com/question/25830314

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The speed of the turtle is 9.41 centimeters per second.

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3 years ago
Mg(OH)2 + 2 HBr à MgBr2 + 2 H2O
AnnyKZ [126]

Explanation:

The balanced equation of the reaction is given as;

Mg(OH)2 (s) + 2 HBr (aq) → MgBr2 (aq) + 2 H2O (l)

1. How many grams of MgBr2 will be produced from 18.3 grams of HBr?

From the reaction;

2 mol of HBr produces 1 mol of  MgBr2

Converting to masses using;

Mass = Number of moles * Molar mass

Molar mass of HBr = 80.91 g/mol

Molar mass of MgBr2 = 184.113 g/mol

This means;

(2 * 80.91 = 161.82g) of HBr produces (1 * 184.113 = 184.113g) MgBr2

18.3g would produce x

161.82 = 184.113

18.3 = x

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2. How many moles of H2O will be produced from 18.3 grams of HBr?

Converting the mass to mol;

Number of moles = Mass / Molar mass = 18.3 / 80.91 = 0.226 mol

From the reaction;

2 mol of HBr produces 2 mol of H2O

0.226 mol would produce x

2 =2

0.226 = x

x = 0.226 * 2 / 2 = 0.226 mol

3. How many grams of Mg(OH)2 are needed to completely react with 18.3 grams of HBr?

From the reaction;

2 mol of HBr reacts with 1 mol of Mg(OH)2

18.3g of HBr =  0.226 mol

2 = 1

0.226 = x

x = 0.226 * 1 /2

x = 0.113 mol

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