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Rasek [7]
2 years ago
5

A ceiling fan is turned on and reaches an angular speed of 132 rev/min in 20 s. It is then turned off and coasts to a stop in an

additional 40 s. The ratio of the average angular acceleration for the first 20 s to that for the last 40 s is which of the following?
a. 2
b. -0.5
c. 0.5
d. -2
Physics
1 answer:
Mkey [24]2 years ago
8 0

Answer:

Explanation:

α = (ωf - ωi)/t

acceleration phase

ωf = 132 rev/min (2π rad/rev / 60 s/min) = 4.4π rad/s

α₁ = (4.4π - 0)/20 = 0.22π rad/s²

α₂ = (0 - 4.4π)/40 = - 0.11π rad/s²

α₁/α₂ = 0.22π/- 0.11π = -2

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Answer:

The answer to your question is

Explanation:

Data

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Formula

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Substitution

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                        T2 = 35 - 63000/2092

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You throw a ball upward with a speed of 14m/s. What is the acceleration of the ball after it leaves your hand? Ignore air resist
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The acceleration of the ball after leaving the hand is 9.8 m/s^2 downward

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In order to find the acceleration of the ball during its motion, we have to study which forces are acting on it.

After the ball leaves the hand, if we neglect air resistance, there is only one force acting on the ball: the force of gravity, whose magnitude is

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where m is the mass of the ball and g is the acceleration of gravity (g=9.8 m/s^2), acting in the downward direction.

According to Newton's second law, the acceleration of the ball is given by

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After the ball leaves the hand, the only force acting on it is the force of gravity, so we can substitute (mg) into the previous equation:

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This means that the acceleration of the ball remains 9.8 m/s^2 downward for the entire motion, after leaving the hand.

Learn more about Newton's second law:

brainly.com/question/3820012

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