Answer:
The answer is 18.12KJ is required to vaporise 48.7 g of dichloromethane at its boiling point
Explanation:
To solve the above question we have the given variable as follows
ΔHvap = heat of vaporisation of dichloromethane per mole = 31.6KJ/mole
However since the heat of vaporisation is the heat to vaporise one mole of dichloromethane, then, for 48.7 grams of dichloromethane, we have.
The number of moles of dichloromethane present = 48.7/84.93 = 0.573 moles
Therefore, the amount of heat required to vaporise 48.7 grams of dichloromethane at its boiling point is 31.6KJ/mole×0.573moles =18.12KJ
P1V1 = P2V2
1.2ATM*(.7 L) = V2 * .95L
V2 = 0.884 Liters or 884.21 ml
Answer:
No.
Materials like water get evaporated when heated, but materials like camphor get sublimed that is they directly get converted into gaseous form when heated, while materials like copper gets melted on heating
