A) The mass is an intrinsic property of an object: it means it depends only on the properties of the object, so it does not depend on the location of the object. Therefore, Gary's mass at 300 km above Earth's surface is equal to his mass at the Earth's surface.
b) The weight of an object is given by

where
m is the mass

is the gravitational acceleration at the location of the object, with G being the gravitational constant, M the mass of the planet and r the distance of the object from the center of the planet.
At the Earth's surface,

, so Gary's weight is

(1)
where m is Gary's mass.
Then, we must calculate the value of g at 300 km above Earth's surface. the Earth's radius is

So the distance of Gary from the Earth's center is

The Earth's mass is

, so the gravitational acceleration is

Therefore, Gary's weight at 300 km above Earth's surface is

(2)
If we compare (1) and (2), we find that Gary's weight has changed by

So, Gary's weight at 300 km above Earth's surface is 91% of his weight at the surface.
Answer:

G= gravitational constant
F= Gravitational force
m= mass of object 1
M= mass of object 2
r= distance between two objects
Answer:
Explanation:
number of turns, N = 149
radius, r = 2.15 cm
Area, A = πr² = 3.14 x 2.15 x 2.15 x 10^-4 = 1.45 x 10^-3 m^2
Change in magnetic field, ΔB = 95.5 - 50.5 = 45 mT = 45 x 10^-3 T
time, Δt = 0.165 second
induced emf
e = N x dФ/dt
where, dФ be the change in flux.
e = N x A x ΔB/Δt
e = 149 x 1.45 x 10^-3 x 45 x 10^-3 / 0.165
e = 0.058 V
1 is b because a runs 20 and b rus 102 is c
Answer:
So do 2400 divided by 70. I got 34.285714 and the numbers behind the decimal are repeating. If you round it you get 34.3