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Sindrei [870]
2 years ago
10

Which statement best explains the importance of resource economics?

Physics
1 answer:
aleksley [76]2 years ago
7 0

Answer:

it sets consistent prices to achieve sustainability

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Question 1 Gary is on the space shuttle. It takes off and lifts him to a height of 300 km above Earth's surface. a. How has Gary
balandron [24]
A) The mass is an intrinsic property of an object: it means it depends only on the properties of the object, so it does not depend on the location of the object. Therefore, Gary's mass at 300 km above Earth's surface is equal to his mass at the Earth's surface.

b) The weight of an object is given by
W=mg
where
m is the mass
g= \frac{GM}{r^2} is the gravitational acceleration at the location of the object, with G being the gravitational constant, M the mass of the planet and r the distance of the object from the center of the planet.

At the Earth's surface, g=9.81 m/s^2, so Gary's weight is
W=mg=9.81 m  (1)
where m is Gary's mass.

Then, we must calculate the value of g at 300 km above Earth's surface. the Earth's radius is 
R=6370 km
So the distance of Gary from the Earth's center is
r=R+h=6370 km+300 km =6670 km = 6.67 \cdot 10^6 m

The Earth's mass is M=5.97 \cdot 10^{24} kg, so the gravitational acceleration is
g'=G \frac{M}{r^2}= (6.67 \cdot 10^{-11} m^3 kg^{-1} s^{-2} )\frac{5.97 \cdot 10^{24} kg}{(6.67 \cdot 10^6 m)^2}=8.95 m/s^2

Therefore, Gary's weight at 300 km above Earth's surface is 
W' = mg' = 8.95 m (2)

If we compare (1) and (2), we find that Gary's weight has changed by
\frac{W'}{W}= \frac{8.95 m}{9.81 m}=0.91
So, Gary's weight at 300 km above Earth's surface is 91% of his weight at the surface.
6 0
3 years ago
What is the equation of universal law of garavitation
Vladimir79 [104]

Answer:

F= \frac{GmM}{ {r}^{2} }

G= gravitational constant

F= Gravitational force

m= mass of object 1

M= mass of object 2

r= distance between two objects

5 0
3 years ago
A 149 turn 149 turn circular coil of radius 2.15 cm 2.15 cm is immersed in a uniform magnetic field that is perpendicular to the
adoni [48]

Answer:

Explanation:

number of turns, N = 149

radius, r = 2.15 cm

Area, A = πr² = 3.14 x 2.15 x 2.15 x 10^-4 = 1.45 x 10^-3 m^2

Change in magnetic field, ΔB = 95.5 - 50.5 = 45 mT = 45 x 10^-3 T

time, Δt = 0.165 second

induced emf

e = N x dФ/dt

where, dФ be the change in flux.

e = N x A x ΔB/Δt

e = 149 x 1.45 x 10^-3 x 45 x 10^-3 / 0.165

e = 0.058 V

4 0
3 years ago
Can someone please help me with science.
vichka [17]
1 is b because a runs 20 and b rus 102 is c
5 0
3 years ago
HELP!!
tresset_1 [31]

Answer:

So do 2400 divided by 70. I got 34.285714 and the numbers behind the decimal are repeating. If you round it you get 34.3

3 0
3 years ago
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