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NNADVOKAT [17]
3 years ago
6

Imagine that you are jumping up and down on a trampoline.

Physics
1 answer:
lions [1.4K]3 years ago
5 0

Answer:

<em />

<em>a. When you are pressing downwards</em><u><em> the energy stored is potential elastic energy due to the elasticity of the stretchy skin.</em></u><em> </em>

<em> </em>

<em>  </em>

<em> </em>

<em>b. When you are high up in the air </em><u><em>the energy stored is potential energy due to your weight and the distance to the ground.</em></u>

<em />

<em>Hope this Helps!</em>

<em />

<em>If you have Any questions Please Ask.</em>

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A 29 foot ladder leans against a building so that the angle between the ground and the ladder is 75 ∘ . How high does the ladder
Aloiza [94]

Answer:

28.01m

Explanation:

Opp/Hyp = Sin

Sin 75 = x/29

x = 29 sin 75

x = 28.01m

3 0
3 years ago
Explain why pumice floats and why ironwood sinks
almond37 [142]

Answer:

A quick way of describing density is to describe an object as heavy or light for its size. Pumice stone, unlike regular rock, does not sink in water because it has a low density. An ironwood branch is very dense and sinks in water.

Hope that helps. x

6 0
2 years ago
Read 2 more answers
ਭਾਰਤ ਵਿੱਚ ਸਭ ਤੋਂ ਵੱਧ ਵਰਖਾ ਕਿੱਥੇ<br>ਹੁੰਦੀ ਹੈ।​
astra-53 [7]

Answer:

I don’t understand:(

3 0
3 years ago
4. What is the formula for potassium dichromateo?b
Gre4nikov [31]

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4 0
2 years ago
(b) If you decrease the length of the pendulum by 25%, how does the new period TN compare to the old period T?
malfutka [58]

Answer:

The new period will be reduced by 50%

Explanation:

The period of pendulum is given by;

T= 2\pi\sqrt{\frac{L}{g} }\\\\\frac{T}{2\pi} = \sqrt{\frac{L}{g} }\\\\(\frac{T}{2\pi} )^2 = {\frac{L}{g}}\\\\\frac{T^2}{4\pi ^2} = {\frac{L}{g}}\\\\T^2(\frac{g}{4\pi ^2}) = L\\\\ \frac{g}{4\pi ^2}= \frac{L}{T^2}\\\\\frac{L_1}{T_1^2} = \frac{L_2}{T_2^2}

When the length is decreased by 25%, the new length L₂ is given by;

L₂ = 25/100(L₁)

L₂ = 0.25L₁

\frac{L_1}{T_1^2} = \frac{L_2}{T_2^2}\\\\T_2^2 = \frac{T_1^2L_2}{L_1} \\\\T_N^2 = \frac{T^2(0.25L_1)}{L_1}\\\\ T_N^2 =0.25T^2\\\\T_N = \sqrt{0.25T^2}}\\\\T_N = 0.5 T

Thus, the new period will be reduced by 50%

8 0
3 years ago
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