One indicator NOT related to domestic violence is

Is the range of the projectile dependent or independent of the projectile's mass? Explain.

Artist 52 [7]

Answer:

independent of the projectiles mass

Explanation:

the range only depends on velocity of projection,angle of projection,acceleration due to gravity.

3 0

3 years ago

Stellar-sized black holes form when a star explodes in a supernova. True or False

svetoff [14.1K]

Answer:

True

Explanation:

Stellar-sized black holes form when a star explodes in a supernova is a true statement. Supernova occurs when a huge size star collapses into itself. This explosion is massive such that parts of the stars are thrown apart. And this phenomenon gives rise to super massive black holes. Supernova occurs when the core becomes very heavy and star is not able to hold its won weight.

4 0

3 years ago

Which is the correct reasoning for why a gamma ray telescope located in Antarctica that is to be used to look for evidence of bl

steposvetlana [31]

Answer:

Well, the options are not given in the questions. But the correct option is:

"Gamma rays do not completely penetrate earth atmosphere."

Explanation:

Most of the gamma rays coming from the stars and sun can not penetrate the earth's atmosphere because atmosphere is as thick to the gamma rays as a 12 foot thick plate of aluminium. They rather absorb in the atmosphere and knock out electrons by reacting with the atoms and produce ions and electrons. These secondary ions and electrons then came to earth during rain fall. Due to this reason gamma ray telescope was not get funded for the study of black holes.

6 0

3 years ago

Read 2 more answers

A 1234 kg freight car moving at 6 m/s runs into a 2468 kg freight car at rest. They stick together upon collision. What was the

kirill [66]

Answer:

2 m/s

Explanation:

Applying,

The law of conservation of momentum

Total momentum before collision = Total momentum after collision

mu+m'u' = V(m+m')............... Equation 1

Where m = mass of the first freight car, m' = mass of the second freight car, u = initial velocity of the first freight car, u' = initial velocity of the second freight car, V = final combined velocity/ speed.

make V the subject of the equation

V = (mu+m'u')/(m+m')........... Equation 2

From the question,

Given: m = 1234 kg, m' = 2468 kg, u = 6 m/s, u' = 0 m/s (at rest)

Substitute these values into equation 2

V = [(1234×6)+(2468×0)]/(1234+2468)

V = 7404/3702

V = 2 m/s

5 0

3 years ago

A worker exerts a pulling force on a box. The worker exerts this force by attaching a rope to the box and pulling on the rope so

shusha [124]

Answer:

<em>The magnitude of the pulling force is 20.66% of the gravitational force acting on the box</em>

Explanation:

<u>Accelerated Motion</u>

The net force exerted on a body is the (vector) sum of all forces applied to the body. The net force can be decomposed in its rectangular components and the dynamics of the body can be studied in each direction x,y separately.

Let's start off by calculating the acceleration the worker gives to the box when pulling it. The distance traveled by the box initially at rest in a time t at an acceleration a is given by

$\displaystyle x=\frac{at^2}{2}$

Solving for a

$\displaystyle a=\frac{2x}{t^2}$

$\displaystyle a=\frac{2\cdot 10}{5.12^2}$

$a=0.763\ m/s^2$

Now we analyze the geometric of the forces applied to the box. Please refer to the free body diagram provided below.

The forces in the y-axis must be in equilibrium since no movement takes place there, thus, being g the acceleration of gravity:

$T_y+N=m.g$

There Ty is the vertical component of the tension of the rope, N is the normal force, and m is the mass of the box

The decomposition of T gives us

$T_y=Tsin\theta$

$T_x=Tcos\theta$

Solving the above equation for N

$Tsin\theta+N=m.g$

$N=m.g-Tsin\theta\text{..........[1]}$

Now for the x-axis, there are two forces acting on the box, the x-component of the tension and the friction force Fr. Those forces are not equilibrated, thus acceleration is produced:

$Tcos\theta-F_r=m.a$