Answer:
4g of NH₃
Explanation:
Hello,
To solve this question, we'll require the equation of reaction.
Equation of reaction
N₂ + 3H₂ → 2NH₃
From the equation of reaction, 1 mole of N₂ reacts with 3 moles of H₂ to produce 2 moles of NH₃.
Number moles = mass / molar mass
Molar mass of H = 1.0g/mol
Mass of H₂ = 2 ×1 = 2g
Molar mass of N₂ = 14.0g/mol
Mass = 2 × 14 = 28g
Molar mass of NH₃ = 17g/mol
Mass = 17g
Therefore, 28g of N₂ reacts with 6g of H₂ to produce 34g of NH₃
I.e 28g + 6g(N₂ + H₂) = 34g of NH₃
34g of (N2 + H2) = 34g of NH₃
4g of (N2 + H2) = x g of NH₃
x = (4 × 34) / 34
x = 4g of NH₃
4g of NH₃ will be produced from 1g of N2 and 3g of H2
