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asambeis [7]
2 years ago
8

1. What are elements and compounds? Give an example of each.

Chemistry
2 answers:
yarga [219]2 years ago
8 0

Answer:

Elements

iron,

copper,

silver,

gold,

hydrogen,

carbon,

nitrogen,

and oxygen.

Compounds

Sugar (sucrose - C12H22O11)

Table salt (sodium chloride - NaCl)

Water (H2O)

Carbon dioxide (CO2)

Sodium bicarbonate (baking soda - NaHCO3)

12345 [234]2 years ago
7 0

Answer:

Well elements are chemical substances while a compound consists of two or multiple elements put together.

Explanation:

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3 years ago
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Which best describes nuclear fusion? O A nucleus spontaneously splits and absorbs energy O Two nuclei spontaneously combine and
KIM [24]

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Is krypton a non-reactive, highly reactive, or radioactive?​
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2 years ago
24.08 x 10^23 atoms of Boron (B) is equal to how many moles of Boron?
padilas [110]
1 mole ----------- 6.02 x 10²³ atoms
? mole ---------- 24.08 x 10²³ atoms

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5 0
3 years ago
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(4) Calculate the % of a compound that can be removed from liquid phase 1 by using ONE to FOUR extractions with a liquid phase 2
maksim [4K]

Answer:

One extraction: 50%

Two extractions: 75%

Three extractions: 87.5%

Four extractions: 93.75%

Explanation:

The following equation relates the fraction q of the compound left in volume V₁ of phase 1 that is extracted n times with volume V₂.

qⁿ = (V₁/(V₁ + KV₂))ⁿ

We also know that V₂ = 1/2(V₁) and K = 2, so these expressions can be substituted into the above equation:

qⁿ = (V₁/(V₁ + 2(1/2V₁))ⁿ = (V₁/(V₁ + V₁))ⁿ =  (V₁/(2V₁))ⁿ = (1/2)ⁿ

When n = 1, q = 1/2, so the fraction removed from phase 1 is also 1/2, or 50%.

When n = 2, q = (1/2)² = 1/4, so the fraction removed from phase 1 is (1 - 1/4) = 3/4 or 75%.

When n = 3, q = (1/2)³ = 1/8, so the fraction removed from phase 1 is (1 - 1/8) = 7/8 or 87.5%.

When n = 4, q = (1/2)⁴ = 1/16, so the fraction removed from phase 1 is (1 - 1/16) = 15/16 or 93.75%.

5 0
3 years ago
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