Answer:
Explanation:
Mass of F / Mass of S = 2.962/1 =2.962 X 32 / 32 = 94.78/32
Mass of F / Mass of S = 2.370 /1 = 2.370 X 32 / 32 = 75.84 /32
Mass of F /Mass of S = 3.555/1 = 3.555 x 32 / 32 = 113.76 / 32 .
Now constant mass of S that is 32 g reacts with different mass of F. They are as follows :
94.78 g , 75.84 g , and 113.76 g
Their ratio = 94.78 : 75.84 : 113.76
divide them by 19
their ratio = 5 : 4 : 6
So these data are consistent with law of multiple proportion.
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Emma here<em>
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Answer:
im pretty sure its decreases going across a row (left to right)
Explanation:
As you move from left to right across a period on the periodic table the size of an atom will decrease
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What name should be used for the ionic compound
LiI?
The name that should be used for
the ionic compound LiI is Lithium iodide. When naming ionic compounds, you have
to take into consideration pairing of two components.
I think its because an egg doesnt have the right chemical make up
Answer:
WCl₂, WCl₄, WCl₅, WCl₆
Explanation:
Molar Mass of Tungsten = 184 g/mol
Mass of Chlorine = 35.5 g/mol
In the first compound;
Percentage of tungsten = 72.17 %
Upon solving;
72.17 % = 184
100 % = Total mass
Total mass of compound = 254.95g
Mass of chlorine = 254.95 - 184 = 70.95 (Dividing by 35.35; This is approximately 2 Chlorine atoms.
The Formular is WCl₂
In the second compound;
Percentage of tungsten = 56.45 %
Upon solving;
56.45 % = 184
100 % = Total mass
Total mass of compound = 325.95 g
Mass of chlorine = 325.95 - 184 = 141.95g (Dividing by 35.35; This is approximately 4 Chlorine atoms.
The Formular is WCl₄
In the third compound;
Percentage of tungsten = 50.91 %
Upon solving;
50.91 % = 184
100 % = Total mass
Total mass of compound = 361.42 g
Mass of chlorine = 361.42 - 184 = 177.42 (Dividing by 35.35; This is approximately 5 Chlorine atoms.
The Formular is WCl₅
In the fourth compound;
Percentage of tungsten = 46.39 %
Upon solving;
46.39 % = 184
100 % = Total mass
Total mass of compound = 396.64 g
Mass of chlorine = 396.64 - 184 = 212.64 (Dividing by 35.35; This is approximately 6 Chlorine atoms.
The Formular is WCl₆
