7). Stopping is an acceleration.
2nd law . . . . . f = m a
Bigger mass needs more force.
Bowling ball has more mass than a golf ball.
9). 2nd law . . . . . f = m a
It doesn't say anything about where the force comes from,
only the size of the force. A child, dog, bird, adult, or
tow-truck have to use the same amount of force to produce
the same result.
10). 2nd law . . . . . f = m a
More acceleration requires more force.
Answer: Option (B) is the correct answer.
Explanation:
It is advised that while conducting an experiment in a laboratory, always perform it under the supervision of your teacher.
When Hiro accidentally touches the liquid then he should immediately tell his teacher about it so that timely precaution can be taken to avoid any damage or side effect. Also, Hiro should rinse his hand in the sink because it will neutralize or decrease the effect of spilled liquid on his skin.
Thus, we can conclude that he should tell his teacher about the spill and rinse his hand in the sink.
The answer for sure is 5 m/s
Answer:
μ = 0.604
Explanation:
For the cat to stay in place on the merry go round, the maximum static frictional force must be equal in magnitude to that of the centripetal force.
Now, Centripetal force is given as;
Fc = mv²/r
Where r is radius and v is tangential speed and m is mass.
We also know that maximum static frictional force is given by;
F_static = μmg
Where μ is coefficient of friction
Now, equating both forces, we have;
mv²/r = μmg
Divide through by m;
v²/r = μg
Now, tangential speed can be expressed as;
v = circumference/period
Thus, v = 2πr/T
Where T is period of rotation and
2πr is the circumference of the merry go round.
Thus,
v²/r = μg is now;
(2πr/T)²/r = μg
Making μ the subject, we have;
(2πr/T)²/rg = μ
μ = [(2π x 5.4)/6]²/(5.4 x 9.8)
μ = 0.604