Here volume of gas is not given so question is solved assuming volume as 1 L.
The number of moles of 1 L gas present in the sealed container at a
pressure of 125 kPa at 25 degrees Celsius is 0.0067 moles.
The ideal gas law equation can be written as
PV = nR T
Here
P is the pressure of the gas in atm
V is the volume it occupies in L
n is the number of moles of gas present in the sample
R is the universal gas constant, equal to 0.0821 atm L/ mol K
T is the absolute temperature of the gas in Kelvin
Now, it's important to realize that the units you have for the volume, pressure, and temperature of the gas must match the unit used in the expression of the universal gas constant.
So
P = 125 kPa
1 atm = 760 kPa
P = 125/760 = 0.1644 atm
T = 25 degree celsius = 25 +273 = 298 K
Taking V = 1 L
So
n = PV/RT
n = 0.1644 x 1 / 0.0821 x 298
n = 0.0067 moles
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Assuming there is no force of friction...
F = ma
F = (1300kg)(1.5m/s^2)
F = 1950N
Just multiply mass by acceleration.
1300 x 1.5 = 1950N.
Answer:
The amplitude of the spring is 32.6 cm.
Explanation:
It is given that,
Mass of the block, m = 2 kg
Force constant of the spring, k = 300 N/m
At t = 0, the velocity of the block, v = -4 m/s
Displacement of the block, x = 0.2 mm = 0.0002 m
We need to find the amplitude of the spring. We know that the velocity in terms of amplitude and the angular velocity is given by :



So, 
A = 0.326 m
or
A = 32.6 cm
So, the amplitude of the spring is 32.6 cm. Hence, this is the required solution.
Answer:
c
Explanation:
because the other would not make sense
The answer is a because it has a high melting tolerance