Explanation:
Let us assume that the given cylinder is 2.6 cm wide and its height is 3.1 cm. And, when piston is pushed down then the steady force is equal to 15 N.
Now, radius of the cylinder will be as follows.
r = 
= 
= 1.3 cm
or, = 0.013 m (as 1 m = 100 cm)
As, area of cylinder = 
= 
= 
Relation between pressure and force is as follows.
Pressure = 
= 
= 25996 
Since, 1 = 1 Pa (as 1 kPa = 1000 Pa)
Therefore, P = 25996
= 25.99 kPa
= 26 kPa (approx)
Thus, we can conclude that pressure of the gas inside the cylinder is 26 kPa.
For this case, in the next item we have gravitational potential energy:
An apple in a tree.
Suppose we define our reference system at the floor level.
Suppose the apple is at a height h from the floor and has mass m.
The gravitational potential energy of the apple is given by:
U = mgh
Where,
m: apple mass
h: height of the apple with respect to the floor
g: acceleration due to gravity
Answer:
C) an apple on a tree
Answer:
The specific kinetic energy of a mass is 0.8 kJ/kg
Explanation:
Given that,
Velocity = 40 m/s
Specific kinetic energy is the kinetic energy per unit mass.
We need to calculate the specific kinetic energy
Using formula of specific kinetic energy
Put the value into the formula
We know that,
1 kJ = 1000 J
or, 1J=0.001 KJ
The specific energy is
Hence, The specific kinetic energy of a mass is 0.8 kJ/kg
To be able to determine the original speed of the car, we use kinematic equations to relate the acceleration, distance and the original speed of the car moving.
First, we manipulate the one of the kinematic equations
v^2 = v0^2 + 2 (a) (x) where v = 0 since the car stopped
Writing the equation in such a way that the initial velocity or v0 is written on one side of the equation,
<span>we get v0 = sqrt (2(a)(x))
Substituting the known values,
v0 = sqrt(2(3.50)(30.0))
v0 = 14.49 m/s
</span>
Therefore, before stopping the car the original speed of the car would be 14.49 m/s
Joules
Watts
Kilocalories
BTU
Electron volt
I can't remember any others. Hope that's enough : )
