Answer:
a) the first vector has magnitude 58 cm and the angle is 15 measured clockwise from the positive side of the x-axis
b) the second vector, the magnitude is 55.7 cm and the angle is 35 half from the negative side of the x-axis in a clockwise direction
c) the magnitude is 54.2 cm with an angle of 18 measured counterclockwise from the x-axis
Explanation:
For this exercise we draw a Cartesian coordinate system in this system: East coincides with the positive part of the x-axis and North with the positive part of the y-axis.
a) the first vector has magnitude 58 cm and the angle is 15 measured clockwise from the positive side of the x-axis
b) the second vector, the magnitude is 55.7 cm and the angle is 35 half from the negative side of the x-axis in a clockwise direction
c) the magnitude is 54.2 cm with an angle of 18 measured counterclockwise from the x-axis
In the attachment we can see the representation of the three vectors
Since the speed of sound is very high, we consider the time period of thunder and lightening negligible.
Now, d = vt
thus, d = 343 x 16.2
thus, d = 5556.6 metres
Thus, we are 5556.6 metres away from lightening ( approximately)
1: decreases, increases, increases, stays the same
2: decreases, increases, increases, stays the same
3: increases, decreases, decreases, stays the same
4: increases, decreases, decreases, stays the same
Answer:
If the absorbed beam is monochromatic (one wavelength) then it excites the H atom to some state n.
When that state decays, some of the atoms may decay to state 1, others to state 2, and still others to state 3
The net energy emitted in such a case would depend on:
n -1, n - 2, n - 3 which would produce 3 different wavelengths