Answer: Concentration of
in the equilibrium mixture is 0.31 M
Explanation:
Equilibrium concentration of
= 0.729 M
The given balanced equilibrium reaction is,

Initial conc. x 0 0
At eqm. conc. (x-2y) M (y) M (3y) M
The expression for equilibrium constant for this reaction will be:
3y = 0.729 M
y = 0.243 M
![K_c=\frac{[y]\times [3y]^3}{[x-2y]^2}](https://tex.z-dn.net/?f=K_c%3D%5Cfrac%7B%5By%5D%5Ctimes%20%5B3y%5D%5E3%7D%7B%5Bx-2y%5D%5E2%7D)
Now put all the given values in this expression, we get :



concentration of
in the equilibrium mixture = 
Thus concentration of
in the equilibrium mixture is 0.31 M
The mass number is the summation of number of proton and neutron present in a nucleus of an atom. For the neutral atom the number of positive charge (number of proton) must be equal to the number of electrons. The number of electrons present in an atom is the atomic number of the atom. The standard way to express the mass number (a) and atomic number (m) of a atom (say X) is
. Now for silicon number of electron or atomic number is 14. And the mass number (a) given 29. Thus the expression nucleus of silicon will be 
Answer:
2.48626 x 10^24
Explanation:
We multiple 4.13 by avogadro's number to get that.
Answer:
this isn't correct answer but the equation is correct by using this methid you can got your answer .
Explanation:
Given - Mass number of atom = 23
Atomic number of atom = 11
As, no. of electrons in an atom is equal to an atomic number of the element.
So, number of electrons = 11
Secondly , number of protons are equal to number of electrons.
so, number of protons = 11
And number of neutrons = mass number - atomic number = 23−11 = 12
so, number of neutrons = 12
So , the atom contains 11 protons, 11 electrons, 12 neutrons.
Answer:
A, B and D
Explanation:
The rate determining step decides the overall rate of reaction and the species involved in the rate determining step determine the overall order of reaction. All the elementary steps in the mechanism sum up to give the overall reaction equation. However, transient intermediates only appear in elementary reaction equations and not the overall reaction equation.