Answer:
solubility of X in water at 17.0 
is 0.11 g/mL.
Explanation:
Yes, the solubility of X in water at 17.0 can be calculated using the information given.
Let's assume solubility of X in water at 17.0 is y g/mL
The geochemist ultimately got 3.96 g of crystals of X after evaporating the diluted solution made by diluting the 36.0 mL of stock solution.
So, solubility of X in 1 mL of water = y g
Hence, solubility of X in 36.0 mL of water = 36y g
So, 36y = 3.96
or, y = 
= 0.11
Hence solubility of X in water at 17.0 is 0.11 g/mL.
A homogeneous mixture is a mixture <span>which has uniform composition and properties throughout - it is identical in its every part. So, having this in mind, the correct answer is C. tap water - </span><span>even though it may have different levels of dissolved minerals and gases.</span>
Answer:
1.42m/s
Explanation:
velocity=displacement/time
v=50/35=1.42m/s
Answer:
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Analytical Chemistry 2.1 (Harvey)
2: Basic Tools of Analytical Chemistry
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2.5: Preparing Solutions
Last updatedAug 10, 2020
2.4: Basic Equipment
2.6: Spreadsheets and Computational Software
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Contributed by David Harvey
Professor (Chemistry and Biochemistry) at DePauw University
Preparing a solution of known concentration is perhaps the most common activity in any analytical lab. The method for measuring out the solute and the solvent depend on the desired concentration and how exact the solution’s concentration needs to be known. Pipets and volumetric flasks are used when we need to know a solution’s exact concentration; graduated cylinders, beakers, and/or reagent bottles suffice when a concentrations need only be approximate. Two methods for preparing solutions are described in this section.
Answer:
Na+Cl2-----NaCl
Explanation:
it's the chemical formula of common salt.
