Answer:
Explanation:
Given that,
The current in the loop, I = 2 A
The radius of the loop, r = 0.4 m
We need to find the magnetic field at a distance 0.09 m along the axis and above the center of the loop. The formula for the magnetic field at some distance is given as follows :
Put all the values,
So, the required magnetic field is equal to .
I'm guessing they rounded because it is technically 2.998 X 108 miles/hour
so I would go with true!
Answer:
Explanation:
graph would be a straight line from (0, 0) to (400, 8)
Plot points are
PE = mgh
50(0) = 0 J
50(2) = 100 J
50(4) = 200 J
50(6) = 300 J
50(8) = 400 J
A motion where gravity is the only force acting upon it
helium group no val elect
mg is reactive when activated. when burned, very intense
pot\asssium 1 valence elect ... KCl eg
theone with H and sodium in it
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