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3 years ago

What is the first thing you have to do if there is a fire in the lab.

Chemistry

1 answer:

sergeinik [125]3 years ago

3 0

The first thing you should do when there is a fire in the laboratory is to <u>alert people</u>.

OSHA is an abbreviation for occupational safety and health administration.

<h3>The main purpose of OSHA.</h3>

The Occupational Safety and Health Administration (OSHA) is an agency of the federal government that is saddled with the following responsibilities:

Assuring and ensuring safe and healthy working conditions for employees or workers.

Setting and enforcing standards, rules, and laws.

Providing education, trainings and assistance to various organizations.

According to the Occupational Safety and Health Administration (OSHA), the first thing a worker or student should do when there is a fire in the laboratory is to <u>alert people</u>.

Read more on fire hazards here: brainly.com/question/17199752

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Brønsted Lowry acid is a proton donor (PD), while a Brønsted-Lowry base is a proton acceptor (PA).

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3 years ago

H2SO4 +HI → __ H2S+12 +H2O balance the equation

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Answer:

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3 years ago

Suppose that 0.250 mol of methane, CH4(g), is reacted with 0.400 mol of fluorine, F2(g), forming CF4(g) and HF(g) as sole produc

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3 years ago

What is the mass of 1.58 moles of CH4

HACTEHA [7]

<h3>Answer:</h3>

25.4 g CH₄

<h3>General Formulas and Concepts:</h3>

<u>Math</u>

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

Brackets
Parenthesis
Exponents
Multiplication
Division
Addition
Subtraction

Left to Right<u> </u>

<u>Chemistry</u>

<u>Atomic Structure</u>

Reading a Periodic Table

<u>Stoichiometry</u>

Using Dimensional Analysis

<h3>Explanation:</h3>

<u>Step 1: Define</u>

1.58 mol CH₄

<u>Step 2: Identify Conversions</u>

[PT] Molar Mass of C - 12.01 g/mol

[PT] Molar Mass of H - 1.01 g/mol

Molar Mass of CH₄ - 12.01 + 4(1.01) = 16.05 g/mol

<u>Step 3: Convert</u>

Set up: $\displaystyle 1.58 \ mol \ CH_4(\frac{16.05 \ g \ CH_4}{1 \ mol \ CH_4})$
Multiply/Divide: $\displaystyle 25.359 \ g \ CH_4$

<u>Step 4: Check</u>

<em>Follow sig fig rules and round. We are given 3 sig figs.</em>

25.359 g CH₄ ≈ 25.4 g CH₄

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Answer:

True :)

Explanation:

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3 years ago

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