Find the distance between two points rounding to the nearest tenth<br> (-7,-1) and (-4,3)

2. A cell with few energy needs would most

sattari [20]

A Cell with few energy needs would most likely contain a small number of Mitochondria.

All cells require energy to function, but cells typically have significant energy needs that can only be met by the mitochondria, the cell's powerhouse.
They transform glucose into ATP, a chemical with a huge energy storage capacity.
Muscles have a large number of mitochondria, allowing them to react rapidly and powerfully to the body's ongoing need for energy.
Macromolecules, defunct cell components, and microbes are all digested by lysosomes.
Vacuoles are typically tiny and aid in the sequestration of waste.
The ribosome, an intercellular structure consisting of both RNA and protein, is where a cell produces new proteins.

Therefore out of all these cell organelles, the cell has fewer mitochondria for less energy need.

Learn more about cell organelles here:

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5 0

2 years ago

Calculate the concentrations of all species present in a 0.26 M solution of ethylammonium chloride (C2H5NH3Cl).

Alina [70]

Answer:

0.00000223

Explanation:

pKa for C2H5NH3+ = 10.7

pKw = 14.0

pKa + pKb = pKw

10.7 + pKb = 14.0

pKb = 14.0 - 10.7

pKb = 3.30

C2H5NH3Cl is a salt of ethylamine and HCl so it will dissolve in water to produce C2H5NH3^+ + Cl^-

The base hydrolysis reaction: C2H5NH3^+(aq) + H2O(l) <=> C2H5NH2(aq) + H3O^+(aq)

This reaction is described by Kb.

Kb = [C2H5NH2][H3O^+]/[C2H5NH3^+]

Let [C2H5NH2] = [H3O^+] = x,

so [C2H5NH3^+] = 0.26 - x

Kb = x^2/(0.26 - x) = 2.00 x 10^-11

Let's solve for x. In this equation, It is possible to solve without the use quadratic equation. So we can assume that 0.26 - x is approximately equal to 0.26. We won't know until we do the calculation.

We get: x^2 + 2.00 x 10^-11x - 4.99 x 10^-12 = 0

With the use of a quadratic calculator.

x = 2.23 x 10^-6 M = [C2H5NH2] = [H3O^+]

0.26 - x is just 0.26 M in this problem because 2.23 x 10^-6 M is insignificant.

[C2H5NH3^+] = 0.26 M = [Cl^-]

NOTE:

pH = -log [H3O^+] = -log(2.23 x 10^-6) = 5.65

Ka is the acid dissociation constant

Kb is the base dissociation constant

5 0

3 years ago

What type pf asexual reproduction produces the most offspring?

slavikrds [6]

thats kinda hot not even gon'

3 0

3 years ago

Read 2 more answers

What is the mass in grams of 394 mL of ethylene glycol? Express your answer with the appropriate units.

AleksandrR [38]

Answer : The mass of ethylene glycol is, 437.34 grams

Solution : Given,

Volume of ethylene glycol = 394 ml

Density of ethylene glycol = 1.11 g/ml (Standard value)

Formula used :

$Density=\frac{Mass}{Volume}$

Now put all the given values in this formula, we get the mass of ethylene glycol.

$1.11g/ml=\frac{Mass}{394ml}$

$Mass=437.34g$

Therefore, the mass of ethylene glycol is, 437.34 grams

3 0

4 years ago

Which of the following reactions would be classified as oxidation-reduction? Check all that apply. View Available Hint(s) Check

erica [24]

Answer:The 1st and 2nd reactions are the example of oxidation -reduction.

Explanation:

Oxidation is basically when a species loses electrons and reduction is basically when the species gains electrons.

A reaction is known as an oxidation -reduction reaction only if oxidation and reduction simultaneously occur in the reaction. It basically means if a species is getting oxidized in the reaction then the other species present in the system must be reduced in the reaction.

Oxidation-reduction reactions are also known as redox reactions.

In the 1st reaction the oxidation state of Na in reactant is 0 and in products is +1 hence Na is oxidized and the oxidation state of chlorine is 0 in reactants and in products is -1 so chlorine is reduced. Hence Na is oxidized and Cl is reduced so the reaction is a example of oxidation-reduction.

2Na(s)+Cl₂(g)→2NaCl(s)

In the second reaction the oxidation state of Na in reactant is 0 and in products is +1 hence Na is oxidized and the oxidation state of Cu is +1 in reactant and 0 in products so Cu is reduced. Hence Na is oxidized and Cu is reduced so the reaction is an example of oxidation-reduction.

Na(s)+CuCl(aq)→NaCl(aq)+Cu(s)

In the third reaction the oxidation state of Na changes from +1 to +1 and that of Cu also changes from +1 to +1. So there is no change in oxidation state of the species present in reactants and products. Hence this reaction is not an example of oxidation and reduction.

6 0

3 years ago

Find the distance between two points rounding to the nearest tenth (-7,-1) and (-4,3)