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lutik1710 [3]
2 years ago
7

Find an expression which represents the sum of (6x – 4) and (-2x + 5) in simplest terms.​

Mathematics
1 answer:
mixer [17]2 years ago
8 0

Answer:

4x+1

Step-by-step explanation:

6x-4-2x+5

4x-4+5

4x+1

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According to the general equation for conditional probability,if p(a upside down u b)= 3/10 and p(b)=4/5 ,What is P(A|B)? A. 1/1
mash [69]
The correct answer for the question that is being presented above is this one: "A. (3/8)." According to the general equation for conditional probability if P(AupsidedownuB) = (3/10) and P(B)= (2/5), then P(A|B) is 3/8.Here are the following choices:A. (3/8)B. (1/2)C. (3/4)D. (1/16)

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3 years ago
X has a normal distribution with the given mean and standard deviation. Find the indicated probability. (Round your answer to fo
lapo4ka [179]

Answer:

0.6247

Step-by-step explanation:

The formula for calculating a Z-score is Z = (X - μ)/σ,

where x is the raw score

μ is the population mean

σ is the population standard deviation.

From the question,

μ = 51, σ = 10. We are to find P(36 ≤ X ≤ 56)

Step 1

Find the Probability of X ≤ 36

μ = 51, σ = 10

Z = (X - μ)/σ

Z = 36 - 51/ 10

Z = -15/10

Z = -1.5

We find the Probability of Z = -1.5 from Z-Table

P(X <36) = P(X = 36) = P(Z = -1.5)

= 0.066807

Step 2

Find the Probability of X ≤ 56

μ = 51, σ = 10

Z = (X - μ)/σ

Z = 56 - 51/ 10

Z = 5/10

Z = 0.5

We find the Probability of Z = 0.5 from Z-Table:

P(X < 56) = P(X = 56) = P(Z = 0.5)= 0.69146

Step 3

Find P(36 ≤ X ≤ 56)

P(36 ≤ X ≤ 56) = P(X ≤ 56) - P(X ≤ 36)

= P( Z = 0.5) - P(Z = -1.5)

= 0.69146 - 0.066807

= 0.624653

Approximately to 4 decimal places , P(36 ≤ X ≤ 56) = 0.6247

7 0
3 years ago
Can someone help me ?
prisoha [69]
I’m pretty sure there are infinite solutions as the system of equations are equivalent to each other.
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3 years ago
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an investment of ​$101 comma 000 was made by a business club. the investment was split into three parts and lasted for one year.
GaryK [48]

Answer:

unknown

Step-by-step explanation:

I am sorry but part of your question is missing

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