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Usimov [2.4K]
2 years ago
15

In the ____ sector; occupations range from maintenance/service technicians, light vehicle technicians, and heavy vehicle technic

ians to service advisers and service managers
Select one:
a. Marketing and technology
b. Service and technology
c. Sales and Marketing
d. Service and retail
Engineering
1 answer:
Len [333]2 years ago
5 0

Answer:

B

Explanation:

becuase this is the best optimal answer when it comes to this particular situation of choice

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What engine or car do you think gets better gas mileage a
defon

Answer:

A muscle care

Explanation:

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3 years ago
Gold forms a substitutional solid solution with silver. Compute the number of gold atoms per cubic centimeter for a silver-gold
evablogger [386]

Answer:

Compute the number of gold atoms per cubic centimeter = 9.052 x 10^21 atoms/cm3

Explanation:

The step by step and appropriate substitution is as shown in the attachment.

From number of moles = Concentration x volume

number of moles = number of particles/ Avogadro's number

Volume = mass/density, the appropriate derivation to get the number of moles of atoms

5 0
3 years ago
If you had a match and a lantern and a candle in the dark which one would you choose to light.
PSYCHO15rus [73]

Answer:

The match

Explanation:

You can light both the lantern and the candle if you light the match first.

I don't know of this is a homework question, but I answered it anyway :)

5 0
3 years ago
Read 2 more answers
When subject to an unknown torque, the shear stress in a 2 mm thick rectangular tube of dimension 100 mm x 200 mm was found to b
laila [671]

Answer:

The shear stress will be 80 MPa

Explanation:

Here we have;

τ = (T·r)/J

For rectangular tube, we have;

Average shear stress given as follows;

Where;

\tau_{ave} = \frac{T}{2tA_{m}}

A_m = 100 mm × 200 mm = 20000 mm² = 0.02 m²

t = Thickness of the shaft in question = 2 mm = 0.002 m

T = Applied torque

Therefore, 50 MPa = T/(2×0.002×0.02)

T = 50 MPa × 0.00008 m³ = 4000 N·m

Where the dimension is 50 mm × 250 mm, which is 0.05 m × 0.25 m

Therefore, A_m = 0.05 m × 0.25 m = 0.0125 m².

Therefore, from the following average shear stress formula, we have;

\tau_{ave} = \frac{T}{2tA_{m}}

Plugging in then values, gives;

\tau_{ave} = \frac{4000}{2\times 0.002 \times 0.0125} = 80,000,000 Pa

The shear stress will be 80,000,000 Pa or 80 MPa.

7 0
3 years ago
In the ____ sector; occupations range from maintenance/service technicians, light vehicle technicians, and heavy vehicle technic
Len [333]

Answer:

B

Explanation:

becuase this is the best optimal answer when it comes to this particular situation of choice

5 0
2 years ago
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