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tamaranim1 [39]
2 years ago
12

1. List five acids and five bases we come across in our day-to-day activities under the correct heading.

Chemistry
1 answer:
shutvik [7]2 years ago
3 0

Answer:

look at the picture

Explanation:

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How many moles of no2 are equivalent to 74.3g of no2
AfilCa [17]
<h3><u>Answer;</u></h3>

= 1.615 moles

<h3><u>Explanation</u>;</h3>

The molar mass of NO2

 = 46.01 g/mol

The mass of NO2 given is 74.3 g

Number moles = mass/ molar mass

                        = 74.3 g/ 46.01 g/mol

                       = 1.615 moles

6 0
3 years ago
Read 2 more answers
Find the mass of oxygen in grams produced by the decomposition of 100.0 g of CO2
SSSSS [86.1K]

The balanced chemical equation is :

2CO_2->2CO+O_2\\\\

Moles of CO_2 ,

n = \dfrac{100\ g}{44.01\ g/mol}\\\\n=2.27\ mol

Now, by given chemical equation , we can see 2 mole of CO_2 react with 1 mole of O_2.

So , 2.27 mole react with :

N=\dfrac{2.27}{2}\ mol\\\\N=1.135\ mol

Mass of oxygen is :

M = N \times 16\\\\M=1.135\times 16\ g\\\\M =18.16\ g

Therefore, mass of oxygen in grams produced is 18.16 g.

Hence, this is the required solution.

7 0
3 years ago
Calculate the enthalpy change (in joules) involved in converting 5.00 grams of water at 14.0 °c to steam at 115 °c under a const
tensa zangetsu [6.8K]

Enthalpy change is the term given to the concentration of the heat absorbed or evolved in a reaction carried out at a constant pressure. It is given by the symbol ΔH.

Enthalpy change = m (Cwater × dT + Hvap + Csteam × dT

dHvap = 40.67 kJ/mol = 40.67 × 103/18 = 2259.4 J/g

Enthalpy change = 5.00 [4.18 × (100-14) + 2259.4 + 1.84 × (115-100)]

= 13232.4 J

7 0
3 years ago
Question 6 (1 point)
Mnenie [13.5K]

Answer:

The correct option is;

d 4400

Explanation:

The given parameters are;

The mass of the ice = 55 g

The Heat of Fusion = 80 cal/g

The Heat of Vaporization = 540 cal/g

The specific heat capacity of water = 1 cal/g

The heat required to melt a given mass of ice = The Heat of Fusion × The mass of the ice

The heat required to melt the 55 g mass of ice = 540 cal/g × 55 g = 29700 cal

The heat required to raise the temperature of a given mass ice (water) = The mass of the ice (water) × The specific heat capacity of the ice (water) × The temperature change

The heat required to raise the temperature of the ice from 0°C to 100°C = 55 × 1 × (100 - 0) = 5,500 cal

The heat required to vaporize a given mass of ice = The Heat of Vaporization × The mass of the ice

The heat required to vaporize the 55 g mass of ice at 100°C = 80 cal/g × 55 g = 4,400 cal

The total heat required to boil 55 g of ice = 29700 cal + 5,500 cal + 4,400 cal = 39,600 cal

However, we note that the heat required to vaporize the 55 g mass of ice at 100°C = 80 cal/g × 55 g = 4,400 cal.

The heat required to vaporize the 55 g mass of ice at 100°C = 4,400 cal

3 0
3 years ago
Hydrogen fuel cells are a promising alternative to gasoline engines in part because they release water instead of carbon dioxide
enot [183]

Answer:

The correct answer is option (B) Two molecules of H2 and a molecule of O2 must collide at one time

Explanation:

2H2(g) + O2(g) → 2 H2O(g)

   2             1            2

Considering the given reaction, for water molecule to be form, two molecules of hydrogen and one molecule of oxygen must collide at the same time. The product obtained from the collision is two molecules of water as steam. 2 H2O(g)

6 0
3 years ago
Read 2 more answers
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