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12345 [234]
2 years ago
10

What is the molar ratio between carbon dioxide to water? 2 C4H10 + 13 O2 = 8 CO2 + 10 H2O

Chemistry
1 answer:
jok3333 [9.3K]2 years ago
6 0

Answer:

8:10

Explanation:

The coefficients of a balanced chemical equation give us the mole ratios. The coefficient of carbon dioxide here is 8 and water is 10.

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When two molecules of methanol (CH3OH) react with oxygen, they combine with three O2 molecules to form two CO2 molecules and fou
Alex17521 [72]

Answer:

188

Explanation:

For every 2 molecules of methanol reacted, 4 molecules of water are formed.  Use this relationship to solve.

2/4 = 94/x

2x = 376

x = 188

188 molecules of water will be formed.

3 0
3 years ago
How many moles of iron is needed to react completely with 5.00 moles of sulfur to form iron
Ghella [55]

Answer:

5 moles of Fe(II) are required to react completely with the 5 moles of Sulphur

Explanation:

The balanced equation in this question is

Iron + Sulfur = Iron(II) Sulfide

Fe (II) + S --> Fe(II)S

Thus one mole of sulfur reacts with one mole of Fe(II)

Hence, 5 moles of Fe(II) are required to react completely with the 5 moles of Sulphur

3 0
2 years ago
Which step is part of a scientific investigation?
Elis [28]
Steps of a scientific investigation include identifying a research question or problem, forming a hypothesis, gathering evidence, analyzing evidence, deciding whether the evidence supports the hypothesis, drawing conclusions, and communicating the results.
3 0
2 years ago
What percentage of a radioactive species would be found as daughter material after six half–lives?
Novosadov [1.4K]
100%.....50%.....25%......12.5%......6.25%......3.125%......1.5625%
...........1............2...........3..............4.................5................6..................

After six half-lives would be found 1.5625% of readioactive species.
3 0
3 years ago
If a pork roast must absorb kJ to fully cook, and if only 10% of the heat produced by the barbecue is actually absorbed by the r
kolezko [41]

Answer:

1,033.56 grams of carbon dioxide was emitted into the atmosphere.

Explanation:

C_3H_8(g)+5O_2(g)\rightarrow 3CO_2(g)+4H_2O(g),\Delta H_{rxn}=-2044 kJ/mol (assuming)

Energy absorbed by pork,E = 1.6\times 10^3 kJ (assuming)

Total energy produced by barbecue = Q

Percentage of energy absorbed by pork = 10%

10\%=\frac{E}{Q}\times 100

Q=\frac{E}{10}\times 100=\frac{1.6\times 10^3 kJ}{10}\times 100=1.6\times 10^4 kJ

Since, it is a energy produced in order to indicate the direction of heat produced we will use negative sign.

Q = -1.6\times 10^4 kJ

Moles of propane burnt to produce Q energy =n

n\times \Delta H_{rxn}=Q

n=\frac{Q}{\Delta H_{rxn}}=\frac{-1.6\times 10^4 kJ}{-2044 kJ/mol}=7.83 mol

According to reaction , 1 mol of propane gives 3 moles of carbon dioxide. then 7.83 moles of will give:

\frac{1}{3}\times 7.83 mol=23.49 mol carbon dioxide gas.

Mass of 23.49 moles of carbon dioxide gas:

23.49 mol × 44 g/mol =1,033.56 g

1,033.56 grams of carbon dioxide was emitted into the atmosphere.

8 0
2 years ago
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