Answer:
The force parallel to the horizontal is 26.24 N
Explanation:
She pulls on the leash with a force F = 30 N, this force, since its at an angle of 29° (i will cal this angle
), it has a force component on x (the horizontal, i will call this force
) and a force component on y (the vertical, i will call this
).
This can be seen in the attached picture.
Since we are asked about the force parallel to the horizontal, we need to find the component of the force
, since
is the adjacent angle, we need to use cosine:
![F_{x}=Fcos \theta](https://tex.z-dn.net/?f=F_%7Bx%7D%3DFcos%20%5Ctheta)
since
and ![\theta=29](https://tex.z-dn.net/?f=%5Ctheta%3D29)
![F_{x}=(30N)cos(29)](https://tex.z-dn.net/?f=F_%7Bx%7D%3D%2830N%29cos%2829%29)
![F_{x}=(30N)(0.8746)](https://tex.z-dn.net/?f=F_%7Bx%7D%3D%2830N%29%280.8746%29)
![F_{x}=26.24N](https://tex.z-dn.net/?f=F_%7Bx%7D%3D26.24N)
The force parallel to the horizontal is 26.24 N
1). Calculate how long it takes an object to fall 4,000 m after it's dropped. (Use D = (1/2) (g) (T²) . D is 4,000 m. g = 9.8 m/s². Find T .)
2). Calculate how far the object will move HORIZONTALLY in that length of time, if it's moving at 75 m/s. (Distance = (75 m/s) x (time) . )
Answer:
Given:
Distance = 35200 miles, time = 2 hr.
So we know = 35200/ 2, = 17600 miles / hr.
They are positive and remain inside the nucleus.