2km*1000=2000m
S=ut+1/2at^2
a=0,thus s=ut
2000=90t
t=2000/90
=22.22s(to 4 s.f)
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There are different types of contact forces like normal Force, spring force, applied force and tension force.
Nothing happens to velocity at all. Speed and direction remain constant.
Answer:
30.46 kgm/s
Explanation:
According to conservation law of momentum, the magnitude of the impulse J that the ground gave the ball equals to the change in momentum of the ball before and after it hits the ground.
Before the hit, the ball velocity is 6m/s, so its momentum is 6 * 2.89 = 17.34 kgm/s
After the hit, the ball velocity is -4.54 m/s in the opposite direction, so its momentum is 2.89*(-4.54) = -13.12 kgm/s
So the change of momentum, and also the impulse is
17.34 - (-13.12) = 30.46 kgm/s
