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krek1111 [17]
2 years ago
13

Electric potential difference is the change in kinetic energy per unit charge in an electric field.

Physics
1 answer:
777dan777 [17]2 years ago
3 0

Hi there!

<u>False. </u>

Electric potential difference is the change in ELECTRIC POTENTIAL ENERGY per unit charge.

\large\boxed{\Delta V = \frac{\Delta U}{q}}

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Answer:

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Explanation:

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5.1 = \frac{10^2 sin(2\theta)}{9.81} \\\\100sin(2\theta) = 50\\\\sin(2\theta) = 0.5\\\\2\theta = sin^{-1}(0.5)\\\\2\theta = 30^0\\\\\theta = 15^0\\\\since \ the \ angle \ occurs \ in \ \ the \ first \ quadrant,\  the \ equivalent \ angle \\ is \ calculated \ as;\\\\90- \theta = 15^0\\\\\theta = 90 - 15^0\\\\\theta = 75^0

<u>Check: </u>

sin(2θ) = sin(2 x 75) = sin(150) = 0.5

sin(2θ) = sin(2 x 15) = sin(30) = 0.5

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