Answer:
Concept: Radiology & Chemistry
- Energy waves are judged based on their wave length, which is measures from one "hump" to the next
- In order from least to greatest, aka increasing: Radio Waves, infrared waves, visible light, UV, x-Ray, and Gamma
- Give brainlist and rate positively
I believe that it is all of the above.
"A Scientific Hypothesis Must Be "Falsifiable". A scientific hypothesis must be testable, but there is a much stronger requirement that a testable hypothesis must meet before it can really be considered scientific."
I hope this helped, have a nice day!
Answer:
The temperature change from the combustion of the glucose is 6.097°C.
Explanation:
Benzoic acid;
Enthaply of combustion of benzoic acid = 3,228 kJ/mol
Mass of benzoic acid = 0.570 g
Moles of benzoic acid = ![\frac{0.570 g}{122.12 g/mol}=0.004667 mol](https://tex.z-dn.net/?f=%5Cfrac%7B0.570%20g%7D%7B122.12%20g%2Fmol%7D%3D0.004667%20mol)
Energy released by 0.004667 moles of benzoic acid on combustion:
![Q=3,228 kJ/mol \times 0.004667 mol=15.0668 kJ=15,066.8 J](https://tex.z-dn.net/?f=Q%3D3%2C228%20kJ%2Fmol%20%5Ctimes%200.004667%20mol%3D15.0668%20kJ%3D15%2C066.8%20J)
Heat capacity of the calorimeter = C
Change in temperature of the calorimeter = ΔT = 2.053°C
![Q=C\times \Delta T](https://tex.z-dn.net/?f=Q%3DC%5Ctimes%20%5CDelta%20T)
![15,066.8 J=C\times 2.053^oC](https://tex.z-dn.net/?f=15%2C066.8%20J%3DC%5Ctimes%202.053%5EoC)
![C=7,338.92 J/^oC](https://tex.z-dn.net/?f=C%3D7%2C338.92%20J%2F%5EoC)
Glucose:
Enthaply of combustion of glucose= 2,780 kJ/mol.
Mass of glucose=2.900 g
Moles of glucose = ![\frac{2.900 g}{180.16 g/mol}=0.016097 mol](https://tex.z-dn.net/?f=%5Cfrac%7B2.900%20g%7D%7B180.16%20g%2Fmol%7D%3D0.016097%20mol)
Energy released by the 0.016097 moles of calorimeter combustion:
![Q'=2,780 kJ/mol \times 0.016097 mol=44.7491 kJ=44,749.1 J](https://tex.z-dn.net/?f=Q%27%3D2%2C780%20kJ%2Fmol%20%5Ctimes%200.016097%20mol%3D44.7491%20kJ%3D44%2C749.1%20J)
Heat capacity of the calorimeter = C (calculated above)
Change in temperature of the calorimeter on combustion of glucose = ΔT'
![Q'=C\times \Delta T'](https://tex.z-dn.net/?f=Q%27%3DC%5Ctimes%20%5CDelta%20T%27)
![44,749.1 J=7,338.92 J/^oC\times \Delta T'](https://tex.z-dn.net/?f=44%2C749.1%20J%3D7%2C338.92%20J%2F%5EoC%5Ctimes%20%5CDelta%20T%27)
![\Delta T'=6.097^oC](https://tex.z-dn.net/?f=%5CDelta%20T%27%3D6.097%5EoC)
The temperature change from the combustion of the glucose is 6.097°C.
1) is chemical Bonds
3) Conservation of mass
5) compound
hope i helped on the ones i could answer