Question

A light has a wavelength of 5.06x10-7m. what is the frequency of the light?

Answer 1

So, the frequency of that light approximately $\sf{\bold{5.93 \times 10^{14} \: Hz}}$

Introduction

Hi ! Here I will help you to discuss the relationship between frequency and wavelength, with the velocity constant of electromagnetic waves in a vacuum. We all know that regardless of the type of electromagnetic wave, it will have the same velocity as the speed of light (light is part of electromagnetic wave too), which is 300,000 km/s or $\sf{3 \times 10^8}$ m/s. As a result of this constant property, the shorter the wavelength, the greater the value of the electromagnetic wave frequency. This relationship can also be expressed in this equation:

$\boxed{\sf{\bold{c = \lambda \times f}}}$

With the following condition :

• c = the constant of the speed of light in a vacuum ≈ $\sf{3 \times 10^{8} \: m/s}$ m/s
• $\sf{\lambda}$ = wavelength (m)
• f = electromagnetic wave frequency (Hz)

Problem Solving

We know that :

• c = the constant of the speed of light in a vacuum ≈ $\sf{3 \times 10^{8} \: m/s}$ m/s
• $\sf{\lambda}$ = wavelength = $\sf{5.06 \times 10^{-7}}$ m.

What was asked :

• f = electromagnetic wave frequency = ... Hz

Step by step :

$\sf{c = \lambda \times f}$

$\sf{3 \times 10^8 = 5.06 \times 10^{-7} \times f}$

$\sf{f = \frac{3 \times 10^8}{5.06 \times 10^{-7}}}$

$\sf{f \approx 0.593 \times 10^{8 - (-7)}}$

$\sf{f \approx 0.593 \times 10^{15}}$

$\boxed{\sf{f \approx 5.93 \times 10^{14} \: Hz}}$

Conclusion :

So, the frequency of that light approximately $\sf{\bold{5.93 \times 10^{14} \: Hz}}$

See More :

• What affects photon energy brainly.com/question/26434060
• What is the foton energy brainly.com/question/26518899