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LuckyWell [14K]
2 years ago
5

A. Driver A falls the greatest distance.

Physics
1 answer:
9966 [12]2 years ago
7 0
A. I just took a quiz on it and A was my answer
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1.
Shalnov [3]

Answer:

No.

Explanation:

Given the following :

Velocity (V) of ball = 5m/s

Radius = 1m

Can the ball reach the highest point of the circular track

of radius 1.0 m?

The highest point in the track could be considered as the diameter of the circle :

Radius = diameter / 2;

Diameter = (2 * Radius) = (2*1) = 2

Maximum height which the ball can reach :

Using the relation :

Kinetic Energy = Potential Energy

0.5mv^2 = mgh

0.5v^2 = gh

0.5(5^2) = 9.8h

0.5 * 25 = 9.8h

12.5 = 9.8h

h = 12.5 / 9.8

h = 1.2755

h = 1.26m

Therefore maximum height which can be reached is 1.26m.

Since h < Diameter

7 0
4 years ago
Is it true that acceleration occurs when there is a change in speed
Amanda [17]
Yes it does. But not always
4 0
3 years ago
Read 2 more answers
During the first 14 minutes of a 1.0 hour trip, a car has an average speed 36 km/h. What must the average speed in km/h of the c
oksian1 [2.3K]

Answer:

85.5 km/h

Explanation:

t_{1} = time interval for first phase = 14 min = \frac{14}{60} h = 0.233 h

t_{2} = time interval for second phase = 46 min = \frac{46}{60} h = 0.767 h

v = average speed for the entire trip = 74 km/h

v_{1} = average speed in first phase = 36 km/h

v_{2} = average speed in second phase

d_{1} = distance traveled in first phase

d_{2} = distance traveled in first phase

average speed is given as

v = \frac{d_{1} + d_{2}}{t_{1} + t_{2}}

v = \frac{v_{1} t_{1} + v_{2} t_{2}}{t_{1} + t_{2}}

74 = \frac{(36) (0.233) + v_{2} (0.767)}{0.233 + 0.767}

74 = (36) (0.233) + v_{2} (0.767)

v_{2} = 85.5 km/h

4 0
4 years ago
Find acceleration. Will give brainliest!
zalisa [80]

Answer:

16200 km/s

270 km/min

4.5 km/h

Explanation:

Acceleration Formula: Average Acceleration = Δv/Δt (change in velocity over change in time)

Simply plug in our known variables and solve:

a = (45.0 - 0)/10

a = 45.0/10

a = 4.5 km/h

7 0
3 years ago
Read 2 more answers
Mercury, a planet in our Solar System, and Callisto, a moon of the planet Jupiter, are about the same size. However, Mercury’s m
TiliK225 [7]
You may jump higher because the more the mass of the planet, the more gravitational force. There is less mass(and gravity) on Callisto so you wouldn’t be weighed down as much and can jump higher. Whereas on Jupiter there is more weight holding you down.
3 0
3 years ago
Read 2 more answers
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