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DerKrebs [107]
2 years ago
9

When the rocket launched the astronauts aboard experienced an acceleration of 32 m/s^2. If one of the astronauts had a mass of 6

5 kg, what net force in newtons did the astronaut experience?
Physics
1 answer:
sergij07 [2.7K]2 years ago
7 0

Answer:

The question is somewhat vague in that acceleration is not exactly defined:

Usually a = (v2 - v1) / t    which would imply that

a = 32 / g = 32 / 9.8 = 3.27   the acceleration due to change in speed of the rocket

One can also say that the astronaut experiences an acceleration of 9.8 m/s^2 just by being motionless on the surface of the earth.

Then a = (32 - 9.8) / 9.8 = 2.27 due to the acceleration of the rocket

If we assume the first condition then

F = 65 kg * 3.27 * 9.8 m/s^2 = 2083 N

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Answer:

v_x=34 m/s

v_y=53.9\ m/s

Explanation:

<u>Horizontal Launch</u>

When an object is thrown horizontally with a speed v from a height h, it describes a curved path ruled by gravity until it eventually hits the ground.

The horizontal component of the velocity is always constant because no acceleration acts in that direction, thus:

vx=v

The vertical component of the velocity changes in time because gravity makes the object fall at increasing speed given by:

v_y=g.t

The horizontal component of the velocity is always the same:

v_x=34 m/s

The vertical component at t=5.5 s is:

v_y=9.8*5.5=53.9

v_y=53.9\ m/s

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nika2105 [10]

Answer:

(a) Acceleration of the bag will be a=16.214m/sec^2  

(B) Weight of the bag will be 137.2 N

Explanation:

We have given mass of the bag m = 14 kg

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(A) According to newtons law we force is equal to F = ma , here m is mass and a is acceleration

So 227=14\times a

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