Explanation:
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a) Alkali metals
=> group 1
=> Li: 1s2 2s => 1s
Na: [Ne] 3s => 3s
K: [Ar] 4s => 4s
Rb: [Kr] 5s => 5s
Cs: [Xe] 6s => 6s
Fr: [Rn] 7s => 7s
=> outer electron configuration is ns, where n is the main energy level: 1, 2, 3, 4, 5, 6,7.
b) Alkaline earth metals
=> group 2 => you have to add 1 electron to the alkaly metal of the same row.
=> Be: [He] 2s2 => 2s2
Mg: [Ne] 3s2 => 3s2
Ca: [Ar] 4s2 => 4s2
Sr: [Kr] 5s2 => 5s2
Ba: [Xe] 6s2 => 6s2
Ra: [Rn[ 7s2 => 7s2
=>outer electron configuration is n s2, where n is the main energy level: 1, 2, 3, 4, 5, 6, 7
c) halogens
=> group 7
=> F: [He] 2s2 2p5 => 2s2 2p5
Cl: [Ne] 3s2 3p5 => 3s2 3p5
Br: [Ar] 3d10 4s2 4p5 => 4s2 4p5
I: [Kr] 4d10 5s2 5p6 => 5s2 5p5
At: [Xe] 4f14 5d10 6s2 6p5
=> outer electron configuration is ns2 np5, where n is the main energy level 1, 2, 3, 4, 5, 6, 7
d) Noble gases
=> group 8
I will show only the outer shell which is what is requested
=> He: 1s2
Ne: ... 2s2 2p6
Ar: ... 3s2 3p6
Kr: ... 4s2 4p6
Xe: ... 5s2 5p6
Rn: ... 6s2 6p6
=> the outer electron configuration is ns2 np6, except for He for which it is 1s2
Evaporation is the process by which water changes from a liquid to a gas or vapor. ... Condensation, the opposite of evaporation, occurs when saturated air is cooled below the ... This does vary geographically, though.
Hello there!
As you may know, pressure and volume have an inverse relationship. This means that as pressure increases, volume decreases (and as volume increases, pressure decreases).
In this problem, the volume of the gas is reduced to 0.250 its original value. This means that the pressure should be higher than it was originally.
We can use Boyle's Law to solve this problem, seeing that temperature is kept constant.
P1V1 = P2V2
Let's rearrange this equation to isolate the variable we need, P2.
P1V1
------- = P2
V2
That's better! Now that we have that down, let's plug in the numbers we were given.
(5.3atm) * (V1)
-------------------- = P2
0.25(V1)
We can get rid of V1, as the number would be equal to 1 (anything divided by itself is equal to 1).
5.3atm
---------- = 21.2 atm
0.25L
Now, while the number is significantly higher, this is quite reasonable.
Let's plug it in and see if we get what we should:
5.3(V1) = (0.25V1)(21.2)
--------
0.25V1
21.2 atm = 21.2 atm
Seems right to me!
Feel free to comment if you need any more help. :)