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vaieri [72.5K]
2 years ago
11

Devise a 6‑step synthesis of the starting material from the product. The cyclopentene is a key intermediate.

Chemistry
1 answer:
Grace [21]2 years ago
7 0

Cyclopentene is industrially produced in large quantities. It is used as a monomer for the synthesis of plastics, in addition to other chemical syntheses.

<h3>The 6‑step synthesis of the starting material from the product</h3>

Reaction 1 - Preparation of keto-aldehyde

Reaction 2 - Preparation of cyclopentene carbaldehyde

Reaction 3 -Preparation of α,β-epoxy-carbaldehyde cyclopentane

Reaction 4 - Preparation of cyclopentene alcohol

Reaction 5 -Preparation of α,β-epoxy-cyclopentane alcohol

Reaction 6 -Preparation of α,β-epoxy-carbaldehyde cyclopentane

With this information we can conclude that cyclopentene is used as a monomer for the synthesis of plastics.

Learn more about synthesis of plastics in brainly.com/question/13833034

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__________ ammonium compounds are less effective against gram-negative bacteria and more effective against gram-positive bacteri
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Quartenary.

Explanation:

Quaternary ammonium compounds (QACs) are cationic salts of organically substituted ammonium compounds and have a broad range of activity against microorganisms, i.e more effective against Gram-positive bacterium at lower concentrations than Gram-negative bacteria.

It was also reported previously that monoalkyl QACs bind by ionic and hydrophobic interactions to microbial membrane surfaces, with the cationic head group facing outwards and the hydrophobic tails inserted into the lipid bilayer, causing the rearrangement of the membrane and the subsequent leakage of intracellular constituents.

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Noble gas notation write the electron configuration for the manganese atom
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<span> the electron configuration for the manganese atom [Ne]3s</span>²
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For carbon monoxide poisoning, the treatment is administration of oxygen at high pressure. This increases the amount of oxyhemog
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Adding oxygen will cause the equation of 
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3 years ago
Water has a boiling point of 100.0°C and a Kb of 0.512°C/m. What is the boiling
Reil [10]

Answer:

The boiling  point of a 8.5 m solution of Mg3(PO4)2 in water is<u> 394.91 K.</u>

Explanation:

The formula for molal boiling Point elevation is :

\Delta T_{b} = iK_{b}m

\Delta T_{b} = elevation in boiling Point

K_{b} = Boiling point constant( ebullioscopic constant)

m = molality of the solution

<em>i =</em> Van't Hoff Factor

Van't Hoff Factor = It takes into accounts,The abnormal values of Temperature change due to association and dissociation .

In solution Mg3(PO4)2 dissociates as follow :

Mg_{3}(PO_{4})_{2}\rightarrow 3Mg^{2+} + 2 PO_{4}^{3-}

Total ions after dissociation in solution :

= 3 ions of Mg + 2 ions of phosphate

Total ions = 5

<em>i =</em> Van't Hoff Factor = 5

m = 8.5 m

K_{b} = 0.512 °C/m

Insert the values and calculate temperature change:

\Delta T_{b} = iK_{b}m

\Delta T_{b} = 5\times 0.512\times 8.5

\Delta T_{b} = 21.76 K

Boiling point of pure water = 100°C = 273.15 +100 = 373.15 K

\Delta T_{b} = T_{b} - T_{b}_{pure}

T_{b}_{pure} = 373.15 K[/tex]

21.76 = T - 373.15

T = 373.15 + 21.76

T =394.91 K

8 0
3 years ago
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