Orbitals that are of equal energy may be referred to as.

A wire carries a current of 6.91 A in a direction that makes an angle of 19◦ with the direction of a magnetic field of strength

g100num [7]

Answer:

4.454 N.

Explanation:

The force on a current carrying conductor in a magnetic field is given as,

F = BILsinФ................... Equation 1

Where F = magnetic Force, B = magnetic Field, I = current, L = Length of the wire, Ф = The angle between the conductor and the Field.

Given: B = 0.289 T, I = 6.91 A, L = 6.7 m, Ф = 19°

Substitute into equation 1

F = 0.289(6.91)(6.7)sin19

F = 0.289×6.91×6.7×0.33

F = 4.454 N.

Hence the magnetic force = 4.454 N.

6 0

4 years ago

A catapult launches a test rocket vertically upward from a well, giving the rocket an initial speed of 80.6 m/s at ground level.

galina1969 [7]

Answer:

44.64 seconds

Explanation:

t = Time taken

u = Initial velocity

v = Final velocity

s = Displacement

a = Acceleration due to gravity = 9.8 m/s²

$v^2-u^2=2as\\\Rightarrow v=\sqrt{2as+u^2}\\\Rightarrow v=\sqrt{2\times 4.2\times 1180+80.6^2}\\\Rightarrow v=128.01\ m/s$

$v=u+at\\\Rightarrow 128.01=80.6+4.2t\\\Rightarrow t=\frac{128.01-80.6}{4.2}=11.29\ s$

Time taken to reach 1180 m is 11.29 seconds

$v=u+at\\\Rightarrow 0=128.01-9.8t\\\Rightarrow t=\frac{128.01}{9.8}=13.06\ s$

Time the rocket will keep going up after the engines shut off is 13.06 seconds.

$v^2-u^2=2as\\\Rightarrow s=\frac{v^2-u^2}{2a}\\\Rightarrow s=\frac{0^2-128.01^2}{2\times -9.8}\\\Rightarrow s=836.05\ m$

The distance the rocket will keep going up after the engines shut off is 836.05 m

Total distance traveled by the rocket in the upward direction is 1180+836.05 = 2016.05 m

The rocket will fall from this height

$s=ut+\frac{1}{2}at^2\\\Rightarrow 2016.05=0t+\frac{1}{2}\times 9.8\times t^2\\\Rightarrow t=\sqrt{\frac{2016.05\times 2}{9.8}}\\\Rightarrow t=20.29\ s$

Time taken by the rocket to fall from maximum height is 20.29 seconds

Time the rocket will stay in the air is 11.29+13.06+20.29 = 44.64 seconds

5 0

3 years ago

15 centimeters 4 millimeters=

nikdorinn [45]

Answer:

what to do with that, I can't answer it

6 0

3 years ago

Find the electric flux passing through the 45° surface of an upright circular cone with a base diameter of 4 m if the electric f

alexgriva [62]

Answer:

electric flux = 177.625 N-m²/C

Explanation:

given data

angle = 45°

diameter = 4 m

electric field E = 20 N/C

to find out

electric flux

solution

we know electric flux formula that is

electric flux = E × A × cosθ ..............1

here A is area that is

Area = πd²/4 = π(4)²/4 = 12.56 m²

now put all value in equation 1

electric flux = 20 × 12.56 × cos45

electric flux = 177.625 N-m²/C

8 0

3 years ago

The second law of thermodynamics allows us to conclude that which of the following statements are true? The second law of thermo

klasskru [66]

Answer:

The disorder in the universe is increasing with time.

Explanation:

The second law of thermodynamics states that the amount of entropy in the universe increases over time. Entropy expresses the number of different configurations that a system defined by macroscopic variables could assume. Therefore, is can be interpreted as a measure of the disorder, or randomness of a system.

7 0

3 years ago