How are momentum and collision related?
1 answer:
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Explanation:
Image distance, v = -17 cm (-ve for virtual image)
Radius of curvature of concave mirror, R = 39 cm
Focal length, f = -19.5 cm (-ve for a concave mirror)
(a) Using mirror's formula as :
u = 132.6 cm
So, the object is placed 132.6 cm in front of the mirror.
(b) Magnification of the mirror,
m = -0.128
Hence, this is the required solution.
Answer:
A) v_average = - 10 km / h, B) v = 1.6 m / s, v = 17.6 m / s
Explanation:
A) the average speed is the average speed of a body, if we assume that the direction of going up the hill is positive
v₁ = 40 km / h
v₂ = - 60 km / h
the average speed is
v_average =
v_average = ( 40 - 60)/2
v_average = - 10 km / h
B) in this case they indicate the acceleration a = 3.2 m / s² and the velocity vo = 9.6 m / s
i) the speed for 2.5 s above
v = v₀ + a t
as the time is earlier
t = - 2.5 s
we substitute
v = 9.6 - 3.2 2.5
v = 1.6 m / s
ii) the velocity for a subsequent time of 2.5 s
t = 2.5 s
we substitute
v = 9.6 + 3.2 2.5
v = 17.6 m / s