Answer:
True
Explanation:
It could either be true or false because you dont really have to be great at something just to do it, you could try new things too.
Pooping problems is not an affect
Answer:
work is 50 kj
Explanation:
Given data
heat (Q) = 50 kj
To find out
work input for the compression stroke per kilogram of air
Solution
we will apply here "first law of thermodynamics" i.e.
The First Law of Thermodynamics states that heat is a form of energy, subject to the principle of conservation of energy, that heat energy cannot be created or destroyed. It can be transferred from one location to another location. i.e.
ΔU = Q – W ................1
here ΔU is change in internal energy, Q is heat and W is work done
here U = 0 because air compressor the compression takes place at a constant internal energy in question
so that by equation 1
Q = W
and Q = 50
so work will be 50 kj
Answer and Explanation:
There four events or stages of reversible nature in a Carnot cycle are:
1. Isothermal expansion of gas
2. Adiabatic expansion
3. Isothermal compression of gas
4.Adiabatic compression of gas
All these 4 processes are reversible processes.
1. A reversible Isothermal expansion of gas takes place in Carnot cycle where an ideal gas absorbs or intake certain quantity of heat from a heat reservoir or source at an elevated temperature which results in the expansion of gas and work is done on the surroundings.
2. A reversible expansion of gas adiabatically takes place in Carnot cycle in an environment with thermal insulation where the gas expand and work is done on the surrounding which results in the lowering of the temperature of the system.
3. A reversible compression of gas isothermally takes place such that the work is done on the system by the surrounding resulting in heat loss.
4. A reversible compression of gas adiabatically, takes place in an environment with thermal insulation and the work is done continuously on the system by the surroundings resulting in the rise in temperature.
Answer:
Explanation:
Sum of the side slope = 2 + 1 = 3
Length of first slope = 2/3 X 3.6 = 2 X 1.2 = 2.4m
Lenght of second slope = 1/3 X 3.6 = 1.2m
Area of the trapezoidal channel = (2.4 + 1.2)/2 X 3.6 = 1.8 X 3.6 = 6.48m²
Alternate dept = 50m³/6.48m²= 7.716m
