Answer: (C) 9.14 . 10⁻³ Ω
Explanation:
The resistance of a resistor, is proportional to his length and inversely proportional to his area, being the proportionality constant a property of the material, called resistivity.
The resistivity is defined as the inverse of the electrical conductivity, which depends on the number of charge carriers and the mobility of these carriers, which is different for each material.
So, we can calculate the resistance as follows:
R = 1/σ . L / A, where:
σ = electrical conductivity, l= length of the wire , A = wire cross-section (assumed circular).
Replacing by the values, we can calculate R as follows:
R = 1/6.1. 10⁷ (Ω.m) . 8.1 m. / π (0.0043)² m / 4 = 9.14 . 10⁻³ Ω
Answer: 16 squared + 63 squared = x squared
Explanation:
Hi, since we have a right triangle we have to apply the Pythagorean Theorem:
c^2 = a^2 + b^2
Where c is the hypotenuse of the triangle (the longest side) and a and b are the other sides.
Replacing with the values given:
x^2 = 63^2 + 16^2
So, the correct option is
16 squared + 63 squared = x squared
Feel free to ask for more if needed or if you did not understand something.
C because it’s in the dmv
Answer:
7.8 Mph
Explanation:
Rate of cycling = 1.1 rev/s
Rear wheel diameter = 26 inches
Diameter of sprocket on pedal = 6 inches
Diameter of sprocket on rear wheel = 4 inches
Circumference of rear wheel = \pi d=26\piπd=26π
Speed would be
\begin{gathered}\text{Rate of cycling}\times \frac{\text{Diameter of sprocket on pedal}}{\text{Diameter of sprocket on rear wheel}}\times{\text{Circumference of rear wheel}}\\ =1.1\times \frac{6}{4}\times 26\pi\\ =134.77432\ inches/s\end{gathered}Rate of cycling×Diameter of sprocket on rear wheelDiameter of sprocket on pedal×Circumference of rear wheel=1.1×46×26π=134.77432 inches/s
Converting to mph
1\ inch/s=\frac{1}{63360}\times 3600\ mph1 inch/s=633601×3600 mph
134.77432\ inches/s=134.77432\times \frac{1}{63360}\times 3600\ mph=7.65763\ mph134.77432 inches/s=134.77432×633601×3600 mph=7.65763 mph
The Speed of the bicycle is 7.8 mph
Answer:
= 2.6906 × 
lb-s/in²
Explanation:
given data
velocity V = 64 in/sec
separated by a gap x = 0.41 in
relative motion by shear stress 
= 0.42 lb/in²
solution
we know that shear stress is directly proportional to rate of change of velocity as per newton's law of viscosity.
....................1
so here coefficient of dynamic viscosity and 
is velocity gradient
and
put here value and we get
0.42 = 
= 2.6906 × lb-s/in²
