Who will win the Copa America 2021 and Euros 2021?

determine the optimum compressor pressure ratio specific thrust fuel comsumption 2.1 220k 1700k 42000 1.004

Afina-wow [57]

Answer:

hello your question is incomplete attached below is the complete question

A) optimum compressor ratio = 9.144

B) specific thrust = 2.155 N.s /kg

C) Thrust specific fuel consumption = 1670.4 kg/N.h

Explanation:

Given data :

Mo = 2.1 , To = 220k , Tt4 = 1700 k, hpr = 42000 kj/kg, Cp = 1.004 kj/ kg.k

γ = 1.4

attached below is the detailed solution

6 0

3 years ago

Elliot wants to show a spherical radius in a technical drawing. Where should he place the symbol “SR” in the drawing?

gogolik [260]

I think it’s ( C with a leader line

4 0

3 years ago

Determine the minimum number of 120-volt, 20-ampere circuit breakers for a continuous load consisting of 63 feet of track lighti

maks197457 [2]

If we have 20-ampere circuit breakers. The number of circuits to the larger whole number is: 13.

<h3>Number of circuits</h3>

Receptacles on a single strap= 180 VA each.

Hence,

VA of the circuit=(Volts x Amperes)/One receptacle

Let plug in the formula

VA of the circuit=(120 volts x 20 amperes)/180 VA

VA of the circuit= 2,400 VA (circuit)/180 VA

VA of the circuit = 13 circuits

Therefore the number of circuits to the larger whole number is: 13.

Learn more about number of circuits here:brainly.com/question/2969220

brainly.com/question/19790289

#SPJ12

4 0

2 years ago

The pump of a water distribution system is powered by a 15-kW electric motor whose efficiency is 90 percent. The water flow rate

wariber [46]

Answer:

Mechanical power of pump is 74.07%.

Explanation:

Power of motor = 15 KW

Efficiency of motor= 90%

So the actual power(P) supplied by motor = 0.9 x 15 KW

P=13.5 KW

Water flow rate = 50 L/s

Volume flow rate = 50 L/s

We know that

$1000\ L/s=1\ m^3/s$

So

$Volume\ flow \rate =0.05\ m^3/s$

We know that pump is an open system and work input for open system can be calculated as

W=VΔP

ΔP is the pressure difference

V is the volume flow rate

So by putting the values

W=0.05 (300-100) (here ΔP=300 - 100=200 KPa)

W=10 KW

So mechanical power of pump

$\eta =\dfrac{W}{P}$

$\eta =\dfrac{10}{13.5}$

η =0.7407

Mechanical power of pump is 74.07%.

6 0

3 years ago

Under the right conditions, it is possible, due to surface tension, to have metal objects float on water. Consider placing a sho

stiv31 [10]

Answer:

D = 0.060732 in

Explanation:

given data

sp. wt. = 500 lb/ft³

diameter = 0.036 in

solution

we get here maximum diameter of rod that is express as

D = $\sqrt{\frac{8 \sigma }{\pi y}}$ ......................1

here $\sigma$ surface tension of water at 60⁰f = 5.03 × $10^{-3}$ lb/ft and y = 500 lb/ft³

so put here value and we will get

D = $\sqrt{\frac{8 \times 5.03 \times 10^{-3} }{\pi \times 500}}$

D = 0.005061 ft

D = 0.060732 in

4 0

3 years ago