Question

A car is merging onto the expressway with an acceleration of 1.77 m/s^2. When it begins down the ramp the car is traveling at a speed of 11.1 m/s. How long will it take for the car to reach a speed of 24.4 m/s

Answer 1

Answer:

time taken = 7.514 seconds

$\sf{acceleration} = \dfrac{\Delta v}{\Delta t} = \dfrac{final \ speed - initial \ speed}{time \ taken}$

Here given:

• acceleration: 1.77 m/s²

• final speed: 24.4 m/s

• initial speed:  11.1 m/s

using the given formula:

$\hookrightarrow \sf{1.77} = \dfrac{24.4 - 11.1}{time \ taken}$

$\hookrightarrow \sf{time \ taken} = \dfrac{24.4 - 11.1}{1.77}$

$\hookrightarrow \sf{time \ taken} = 7.514 \ seconds$

Answer 2

Formula :

$\frac{final \: speed - initial \: speed}{time \: taken}$

Given :

• acceleration: 1.77 m/s²

• final speed: 24.4 m/s

• initial speed: 11.1 m/s

Solution :

$1.77 = \frac{24.4 - 11.1}{time \: taken}$

$time \: taken = \frac{24.4 - 11.1}{1.77}$

$taken \: time = 7.514 \: seconds$