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2 years ago

Pahelp po, 1-5 only, tyy

Mathematics

1 answer:

siniylev [52]2 years ago

6 0

Answer:

1. 9

2. 25

3. 12

4. 13

5. 75.36

Step-by-step explanation:

You should pay attention in class

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A sector of a circle of 7cm has an area of 44cm².calculate the angle of the sector,correct to the nearest degree π =22\7

Hitman42 [59]

Answer:

$\theta=102.85^{\circ}$

Step-by-step explanation:

Given that,

The radius of circle, r = 7 cm

The area of sector, A = 44cm²

We need to find the angle of the sector. The formula for the area of sector is given by :

$A=\dfrac{\theta}{360}\pi r^2$

Solve for $\theta$ .

$\theta=\dfrac{360A}{\pi r^2}\\\\\theta=\dfrac{360\times 44}{\dfrac{22}{7}\times 7^2}\\\\\theta=102.85^{\circ}$

So, the angle of the sector is equal to $102.85^{\circ}$ .

7 0

3 years ago

Baker made 5 pounds of icing. He used 4/9 of the icing to decorate. How much did he have left over?

Elena L [17]

If the baker made 5 pounds of icing and used 4/9 of the icing to make decorations, then he used:

5 * 4/9 =
= 20/9 =
= 2 2/9 [of icing]

To find out how much he has left over, we just need to substract 2 2/9 from 5:

5 - 2 2/9 =
= 3 - 2/9 =
= 2 7/9

Answer: The baker has <u>2 7/9</u> of the icing left.

6 0

3 years ago

The diameter of a semicircle is 6 miles. What is the semicircle's perimeter?

koban [17]

Answer:

$15.42mi$

Step-by-step explanation:

Use the formula for a semicircle's perimeter.

$P=\frac{1}{2}\pi *d+d$

Plug in 6 for d.

$P=\frac{1}{2}\pi*6+6$

Let's use 3.14 for $\pi$ , just to make it easier, but of course, if it states to round it to something else, just plug in that many values for $\pi$ .

$P=\frac{1}{2}(3.14)*6+6 \\ \\ P=1.57*6+6 \\ \\ P=9.42+6 \\ \\ P=15.42$

5 0

3 years ago

Read 2 more answers

tenesa bought a 50 pound bag of flour for her bakery. she used 13.65 pounds of flour. how many pounds of flour are left in the b

saw5 [17]

Answer: 36.35

work:
50 - 13.65 = 36.35

4 0

3 years ago

Read 2 more answers

6 points

kodGreya [7K]

Answer:

$y=-2\,(x+3)^2-3$

Step-by-step explanation:

Notice that they are asking you to write the equation of the parabola in vertex form, that is using the coordinates of the vertex $(x_v,y_v)$ in the expression:

$y-y_v=a\,(x-x_v)^2\\y=a\,(x-x_v)^2+y_v$

we can start by directly replacing the given vertex coordinates (-3, -3) in the expression, and then using the extra info on the point the parabola goes through in order to find the parameter $a$ :

$y=a\,(x-x_v)^2+y_v\\y=a\,(x+3)^2+(-3)\\y=a\,(x+3)^2-3\\-5=a\,(-2+3)^2-3\\-5=a\,(1)-3\\a=-5+3\\a=-2$

So, now we can write the full expression for the parabola:

$y=a\,(x+3)^2-3\\y=-2\,(x+3)^2-3$

8 0

3 years ago