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3 years ago

Why does the rate of a reaction increase when the concentration of reactants is increased?

Chemistry

1 answer:

leva [86]3 years ago

5 0

If reactants eventually collide, there is an occurrence of reaction.

Therefore, when there is an increase concentration of reactant, meaning to say that there are several moles of it every unit volume. An example of this is a room having hundred of people will absolutely get higher concentration compared to a room with one individual only.

Pertaining to effective collisions, if ever there is an increase of concentration, the frequency and rate of effective collisions among reactants surges in such a way that the rate of reaction also surges. Same with passing into a room with only 1 individual compared to hundred people blind persons, you probably want to proceed to the room with several people.

This is the simple logic behind that scientific existence.

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385 J of heat are needed to heat a piece of aluminum from 22°C to 45°C. If the specific heat of Al is 0.90 J/g°C, what is the ma

VikaD [51]

Answer:

M of Al=33.09g or 0.0331kg

Explanation:

Heat Energy= specific heat*mass*change in temperature

H=M*C*T

make M subject of the formula

M=H/CT

M=685J/0.90J/g°C*(45°C-22°C)

M=685J/0.90J/g°C*23°C

M=685J/20.7J/g

M=33.09g or 0.0331kg

4 0

3 years ago

9.Out of the following which is a poly atomic molecule. (H2, CI 2.03.)

Vikki [24]

the poly atomic molecule is H2

3 0

3 years ago

3. A student carries out the clay-catalyzed dehydration of cyclohexanol starting with 10 moles of cyclohexanol and obtains 500 m

IrinaK [193]

Answer:

$49.45~%$

Explanation:

In this case, we have to start with the chemical reaction:

$C_6H_1_2O~->~C_6H_1_0~+~H_2O$

So, if we start with 10 mol of cyclohexanol ( $C_6H_1_2O$ ) we will obtain 10 mol of cyclohexanol ( $C_6H_1_0$ ). So, we can calculate the grams of cyclohexanol if we calculate the molar mass:

$(6*12)+(10*1)=82~g/mol$

With this value we can calculate the grams:

$10~mol~C_6H_1_0\frac{82~g~C_6H_1_0}{1~mol~C_6H_1_0}=820~g~C_6H_1_0$

Now, we have as a product 500 mL of $C_6H_1_0$ . If we use the density value (0.811 g/mL). We can calculate the grams of product:

$500~mL\frac{0.811~g}{1~mL}=405.5~g$

Finally, with these values we can calculate the yield:

$%~=~\frac{405.5}{820}x100~=~49.45%$ %= (405.5/820)*100 = 49.45 %

See figure 1

I hope it helps!

6 0

3 years ago

A solute that has been dissolved in a solvent ________.

grigory [225]

Answer:

a solution: for example when sugar is dissolved in water it becomes a sugar solution

8 0

2 years ago

What is the crucial element of a good hypothesis?

photoshop1234 [79]

The qualities of a good hypothesis are: 1) Logically consistent with other theories and data 2) Have explanatory power 3) Be empirically testable 4) Similar hypothesis is the better hypothesis.

4 0

3 years ago