What is monochromatic light
2 answers:
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We know that to relate solutions of with the factors of molarity and volume, we can use the equation: 
**NOTE: The volume as indicated in this question is defined in L, not mL, so that conversion must be made. However it is 1000 mL = 1 L.
So now we can assign values to these variables. Let us say that the 18 M
is the left side of the equation. Then we have:
We can then solve for
:
and 
or 
We now know that the total amount of volume of the 4.35 M solution will be 210 mL. This is assuming that the entirety of the 50 mL of 18 M is used and the rest (160 mL) of water is then added.
**NOTE: The volume as indicated in this question is defined in L, not mL, so that conversion must be made. However it is 1000 mL = 1 L.
So now we can assign values to these variables. Let us say that the 18 M
We can then solve for
We now know that the total amount of volume of the 4.35 M solution will be 210 mL. This is assuming that the entirety of the 50 mL of 18 M is used and the rest (160 mL) of water is then added.
Answer:
26.25 mL
Explanation:
This is a dilution problem. First, let us calculate the volume of final solution needed:
The dog weighs 50 pounds and the sedative is administered at 0/7 ml per pound. Hence:
50 x 0.7 = 35 mL
A total volume of 35 mL, 2.5% solution of the sedative will be needed.
But 10% solution is available. There needs to be a dilution with saline water, but what volume of the 10% solution would be diluted?
initial volume = ?
final volume = 35 mL
initial concentration = 10%
final concentration = 2.5%
Using dilution equation:
initial concentration x initial volume = final concentration x final volume
initial volume =
= 2.5 x 35/10 = 8.75 mL
Hence, 8.75 mL of the 10% pre-mixed sedative will be required.
But 35 mL is needed? The 8.75 mL is marked up to 35 mL with saline water.
35 - 8.75 = 26.25 mL
<em>Therefore, 26.25 mL of saline water will be added to 8.75 mL of the 10% pre-mixed sedative to give 2.5%, 35 mL needed for the dog.</em>